Question

[Tô Nguyễn Minh Anh]

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Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 2:

a: \(x+\dfrac{3}{7}=\dfrac{16}{7}\)

=>\(x=\dfrac{16}{7}-\dfrac{3}{7}=\dfrac{13}{7}\)

b: \(x-\dfrac{2}{5}=\dfrac{4}{5}\)

=>\(x=\dfrac{4}{5}+\dfrac{2}{5}=\dfrac{6}{5}\)

c: \(x-\dfrac{4}{5}=\dfrac{3}{10}\)

=>\(x=\dfrac{3}{10}+\dfrac{4}{5}=\dfrac{3}{10}+\dfrac{8}{10}=\dfrac{11}{10}\)

d: \(x+\dfrac{7}{6}=\dfrac{29}{18}\)

=>\(x+\dfrac{21}{18}=\dfrac{29}{18}\)

=>\(x=\dfrac{8}{18}=\dfrac{4}{9}\)

e: \(\dfrac{7}{5}-x=\dfrac{3}{15}\)

=>\(\dfrac{7}{5}-x=\dfrac{1}{5}\)

=>\(x=\dfrac{7}{5}-\dfrac{1}{5}=\dfrac{6}{5}\)

f: \(\dfrac{20}{12}-x=\dfrac{4}{6}\)

=>\(\dfrac{5}{3}-x=\dfrac{2}{3}\)

=>\(x=\dfrac{5}{3}-\dfrac{2}{3}=\dfrac{3}{3}=1\)

Bài 1:

\(\dfrac{5}{6}+\dfrac{7}{6}=\dfrac{5+7}{6}=\dfrac{12}{6}=2\)

\(\dfrac{19}{12}-\dfrac{16}{12}=\dfrac{19-16}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)

\(\dfrac{3}{5}+\dfrac{15}{20}=\dfrac{12}{20}+\dfrac{15}{20}=\dfrac{27}{20}\)

\(\dfrac{17}{25}-\dfrac{2}{5}=\dfrac{17}{25}-\dfrac{10}{25}=\dfrac{7}{25}\)

\(\dfrac{7}{18}+\dfrac{2}{3}=\dfrac{7}{18}+\dfrac{12}{18}=\dfrac{19}{18}\)

\(\dfrac{27}{24}-\dfrac{5}{6}=\dfrac{27}{24}-\dfrac{20}{24}=\dfrac{7}{24}\)

\(\dfrac{27}{35}+\dfrac{4}{5}=\dfrac{27}{35}+\dfrac{28}{35}=\dfrac{55}{35}=\dfrac{11}{7}\)

\(\dfrac{9}{5}-\dfrac{9}{10}=\dfrac{18}{10}-\dfrac{9}{10}=\dfrac{9}{10}\)