Câu hỏi của Hiền Nguyễn

Question

B=$\dfrac{6}{19}\cdot\dfrac{-7}{11}+\dfrac{6}{19}\cdot\dfrac{-4}{11}+\dfrac{-13}{19}$

Đức Minh · Accepted Answer

$B=\dfrac{6}{19}\cdot\dfrac{-7}{11}+\dfrac{6}{19}\cdot\dfrac{-4}{11}+\dfrac{-13}{19}$

$B=\dfrac{6}{19}\cdot\left(-\dfrac{4}{11}+\dfrac{-7}{11}\right)+\dfrac{-13}{19}$

$B=\dfrac{6}{19}\cdot\left(-1\right)+\dfrac{-13}{19}$

$B=-\dfrac{6}{19}+\dfrac{-13}{19}=-\dfrac{19}{19}=-1$

Vậy $B=-1$Câu trả lời: $B=\dfrac{6}{19}\cdot\dfrac{-7}{11}+\dfrac{6}{19}\cdot\dfrac{-4}{11}+\dfrac{-13}{19}$

$B=\dfrac{6}{19}\cdot\left(-\dfrac{4}{11}+\dfrac{-7}{11}\right)+\dfrac{-13}{19}$

$B=\dfrac{6}{19}\cdot\left(-1\right)+\dfrac{-13}{19}$

$B=-\dfrac{6}{19}+\dfrac{-13}{19}=-\dfrac{19}{19}=-1$

Vậy $B=-1$

Hiền Nguyễn · Answer

THANK BANCâu trả lời: THANK BAN