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a ) \(1\frac{1}{2}+2\frac{1}{3}+3\frac{1}{6}-5\)
\(=\frac{3}{2}+\frac{7}{3}+\frac{19}{6}-\frac{5}{1}\)
\(=\frac{9}{6}+\frac{14}{6}+\frac{19}{6}-\frac{30}{6}\)
\(=\frac{23}{6}+\frac{19}{6}-\frac{30}{6}\)
\(=\frac{42}{6}-\frac{30}{6}\)
\(=\frac{12}{6}=2\)
b ) \(2\frac{2}{3}\times3\frac{3}{4}\div4\frac{4}{5}\)
\(=\frac{8}{3}\times\frac{15}{4}\div\frac{24}{5}\)
\(=\frac{120}{12}\div\frac{24}{5}\)
\(=\frac{120}{12}\times\frac{5}{24}\)
\(=\frac{600}{288}=\frac{25}{12}\)
c ) \(4\frac{1}{5}+5\frac{1}{3}-2\frac{2}{3}\times3\frac{1}{5}+\frac{9}{25}\div\frac{9}{20}\)
\(=\frac{21}{5}+\frac{16}{3}-\frac{8}{3}\times\frac{16}{5}+\frac{9}{25}\div\frac{9}{20}\)
\(=\frac{63}{15}+\frac{80}{15}-\frac{128}{15}+\frac{9}{25}\times\frac{20}{9}\)
\(=\frac{143}{15}-\frac{128}{15}+\frac{180}{225}\)
\(=\frac{15}{15}+\frac{12}{15}\)
\(=\frac{27}{15}=\frac{9}{5}\)
1.Chuyển các hỗn số sau thành phân số:
\(2\frac{1}{3}\)= \(\frac{7}{3}\)
\(4\frac{2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{12}{4}\)
\(9\frac{5}{7}=\frac{68}{7}\)
\(10\frac{3}{10}=\frac{103}{10}\)
2.Chuyển các hỗn số thành phân số rồi thực hiện phép tính:
\(\alpha.\)\(2\frac{1}{3}+4\frac{1}{3}=\frac{7}{3}+\frac{13}{3}=\frac{20}{3}\)
b. \(9\frac{2}{7}+5\frac{3}{7}=\frac{65}{7}+\frac{38}{7}=\frac{103}{7}\)
c. \(10\frac{3}{10}+4\frac{7}{10}=\frac{103}{10}+\frac{47}{10}=\frac{150}{10}\)=\(15\)
d. \(2\frac{1}{3}+5\frac{1}{4}=\frac{7}{3}+\frac{21}{4}=\frac{21}{12}+\frac{63}{12}=\frac{84}{12}\)= 7
e. \(3\frac{2}{5}+2\frac{1}{7}=\frac{17}{5}+\frac{15}{7}=\frac{119}{35}+\frac{75}{35}=\frac{194}{35}\)
g. \(8\frac{1}{6}+2\frac{1}{7}=\frac{49}{6}+\frac{15}{7}=\frac{342}{42}+\frac{90}{42}=\frac{432}{42}\)
\(8\frac{7}{10}+2\frac{3}{4}=\frac{87}{10}+\frac{11}{4}=\frac{174}{20}+\frac{55}{20}=\frac{229}{20}\)
Bạn chỉ cần đưa về phân số xong tính bình thường. Muốn đổi từ hỗn số sang phân số, ta chỉ cần lấy phần nguyên nhân cho mẫu rồi cộng với tử là xong. Chứ bạn cứ hỏi mấy bài dễ như thế này thì k giỏi đc đâu!!!
3/2+5/3
=19/6
8/3-11/7
=23/21
8/3*21/4
=168/12=14
7/2:9/4
=7/2*4/9
=28/18=10//9
\(1\frac{1}{2}+1\frac{1}{3}=\frac{3}{2}+\frac{4}{3}=\frac{9}{6}+\frac{8}{6}=\frac{17}{6}\)
\(2\frac{2}{3}-1\frac{4}{7}=\frac{8}{3}-\frac{11}{7}=\frac{56}{21}-\frac{33}{21}=\frac{23}{21}\)
\(2\frac{2}{3}\cdot5\frac{1}{4}=\frac{8}{3}.\frac{21}{4}=14\)
\(3\frac{1}{2}:2\frac{1}{4}=\frac{7}{2}:\frac{9}{4}=\frac{7}{2}.\frac{4}{9}=\frac{14}{9}\)
\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)
\(=3+\frac{2}{5}+\frac{3}{5}\)
\(=3+1\)
\(=4\)
\(3\frac{2}{5}=\frac{3\cdot5+2}{5}=\frac{17}{5}\)
\(2\frac{1}{7}=\frac{2\cdot7+1}{7}=\frac{15}{7}\)
\(8\frac{1}{6}=\frac{8\cdot6+1}{6}=\frac{49}{6}\)
\(2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{5}{2}\)
\(3\frac{2}{5}\cdot2\frac{1}{7}=\frac{17}{5}\cdot\frac{15}{7}=\frac{51}{7}\)
\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{49}{6}\cdot\frac{2}{5}=\frac{49}{15}\)
\(\frac{23}{12}\)
\(\frac{314}{105}\)
\(\frac{59}{60}\)
\(\frac{199}{90}\)
\(\frac{1}{18}\)
\(\frac{13}{36}\)
\(\frac{4}{221}\)
\(\frac{4}{85}\)
1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
\(3\frac{1}{3}+2\frac{1}{2}=\frac{6}{3}+\frac{5}{2}=\frac{9}{2}\)
\(4\frac{5}{6}-3\frac{3}{4}=\frac{26}{6}-\frac{15}{4}=\frac{7}{12}\)
\(2\frac{2}{3}\times2\frac{4}{5}=\frac{8}{3}\times\frac{14}{5}=\frac{112}{15}\)
\(4\frac{1}{2}:3\frac{1}{7}=\frac{9}{2}:\frac{22}{7}=\frac{63}{44}\)