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<=> 1+2+3+...+x=91
<=> x(x+1)/2=91
<=>x2+x-182=0
<=> x=13 hoặc x=-14(loại)
Vậy x=13
1/3(2x-5)=-2/3-3/2=-13/6
2x-5=-13/6:1/3=-13/2
2x=-13/2+5
2x=-3/2
x=-3/2:2=-3/4
Trương Ứng Hòa
Tìm x biết:
a,x-5/7=1/9
b,2x/5=6/2x+1
c,11/8+13/6=85/x
d,2x-2/11=1.1/5
e,x/15=3/5+-2/3
f,x/182=-6/14.35/91
a, \(x\) - \(\dfrac{5}{7}\) = \(\dfrac{1}{9}\)
\(x\) = \(\dfrac{1}{9}\) + \(\dfrac{5}{7}\)
\(x\) = \(\dfrac{52}{63}\)
b, \(\dfrac{2x}{5}\) = \(\dfrac{6}{2x+1}\)
2\(x\).(2\(x\) + 1) = 30
4\(x^2\)+ 2\(x\) - 30 = 0
4\(x^2\) + 12\(x\) - 10\(x\) - 30 = 0
(4\(x^2\) + 12\(x\)) - (10\(x\) + 30) =0
4\(x\).(\(x\) + 3) - 10.(\(x\) +3) = 0
2 (\(x\) + 3).(2\(x\) - 5) = 0
\(\left[{}\begin{matrix}x+3=0\\2x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-3\\x=\dfrac{5}{2}\end{matrix}\right.\)
Vậy \(x\) \(\in\) {-3; \(\dfrac{5}{2}\)}
a/ \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{37}{70}\)
Vậy....
b/ \(x+\dfrac{4}{5}=-\dfrac{5}{12}\cdot\dfrac{3}{25}\)
\(x+\dfrac{4}{5}=-\dfrac{1}{20}\)
\(x=-\dfrac{1}{20}-\dfrac{4}{5}=-\dfrac{17}{20}\)
Vậy....
c/ \(\dfrac{x}{182}=-\dfrac{6}{12}\cdot\dfrac{35}{91}\)
\(\dfrac{x}{182}=-\dfrac{5}{26}\)
\(=>x\cdot26=-5\cdot182\)
\(26x=-910\)
\(x=-910:26=-35\)
Vậy....
a) Ta có: \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(\Leftrightarrow x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{7}{70}+\dfrac{30}{70}\)
hay \(x=\dfrac{37}{70}\)
Vậy: \(x=\dfrac{37}{70}\)
a) \(x-\frac{5}{7}=\frac{1}{9}\Rightarrow x=\frac{1}{9}+\frac{5}{7}\Rightarrow x=\frac{52}{63}\)
b) \(\frac{-3}{7}-x=\frac{4}{5}+\frac{-2}{3}\Rightarrow\frac{-3}{7}-x=\frac{2}{15}\Rightarrow x=\frac{-3}{7}-\frac{2}{15}\Rightarrow x=\frac{-59}{105}\)
c) \(x-\frac{1}{5}=\frac{2}{7}.\frac{-11}{5}\Rightarrow x-\frac{1}{5}=\frac{-22}{35}\Rightarrow x=\frac{-22}{35}+\frac{1}{5}\Rightarrow x=\frac{-3}{7}\)
d) \(\frac{x}{182}=\frac{-6}{14}.\frac{35}{91}\Rightarrow\frac{x}{182}=\frac{-15}{91}\Rightarrow x=\frac{\left(-15\right).182}{91}\Rightarrow x=-30\)
a)-(2x + 15 ) + 13 = -234
\(\Leftrightarrow\)-2x-15+13+234=0
\(\Leftrightarrow\)2x=232
\(\Leftrightarrow\)x=116
b)2+4+6+8 +..............+2x=182
\(\Leftrightarrow\)2(1+2+3+4+.....+x) =182
\(\Leftrightarrow\)1+2+3+4+.....+x= 182/2 = 91
\(\Leftrightarrow\)x(x+1)/2 =91
\(\Leftrightarrow\)x(x+1)= 182
\(\Leftrightarrow\)x(x+1) = 13(13+1)
\(\Leftrightarrow\)\(\hept{\begin{cases}x=13\\x+1=13+1\end{cases}}\Leftrightarrow x=13\)
Vậy...
a) (-68) + (-72) + 2017 + (-28) + 168
= (-68 + 168) + [(-72) + (-28)] + 2017
= 100 + (-100) + 2017
= 0 + 2017
= 2017
Bài 9:
a) 15x + 40 = 15 + 20.8
15x + 40 = 15 + 160
15x + 40 = 175
15x = 175 - 40 = 135
x = 135 / 15 = 9
b) ( x-1 )( 5-x ) = 0
=> x-1 = 0 hoặc 5-x = 0
+) x-1 = 0 +) 5-x = 0 ( còn lại tự làm nhé ^^ )
c) x - 140 : 35 = 270
x - 140 = 270 . 35 = 9450
x = 9450 + 140 = 9590
d) ( 14 - 3x ) + ( 6 + x ) = 0
14 - 3x + 6 + x = 0
( 14 + 6 ) - ( 3x -x ) = 0
20 - 2x = 0
2x = 20
x = 10
190 - 2 ( 2.X - 6 ) = 182
=> 2( 2.X - 6) = 190 - 182 = 8
=> 2.X - 6 = 8 : 2 = 4
=> 2.X = 4 + 6 = 10
=> X = 10 : 2 = 5
=> X = 5
190 - 2 . (2 . x - 6) = 182
2 . (2 . x - 6) = 190 - 182
2 . (2 . x - 6) = 8
2 . x - 6 = 8 : 2
2 . x - 6 = 4
x - 6 = 4 : 2
x - 6 = 2
x = 2 + 6
x = 8
Vậy x = 8
Trả lời:
190 - 2 ( 2x - 6 ) = 182
=> 2 ( 2x - 6 ) = 190 - 182
=> 2 ( 2x - 6 ) = 8
=> 2x - 6 = 8 : 2
=> 2x - 6 = 4
=> 2x = 4 + 6
=> 2x = 10
=> x = 5
Vậy x = 5