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a) \(\frac{58}{19}+\frac{13}{17}+\frac{35}{43}+\frac{119}{19}+\frac{8}{43}\)
\(=\frac{13}{17}+\left(\frac{58}{19}+\frac{119}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)\)
\(=\frac{13}{17}+\frac{204}{19}+1\)
\(=\frac{1808}{133}\)
b) \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{13}{4}\)
\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{13}{4}\)
\(=\frac{-5}{7}.1+\frac{13}{4}\)
\(=\frac{71}{28}\)
c) \(\frac{146}{13}-\left(\frac{21}{7}+\frac{68}{13}\right)\)
\(=\left(\frac{164}{13}-\frac{68}{13}\right)+3\)
\(=\frac{135}{13}\)
d) \(\frac{2}{7}.\frac{21}{4}-\frac{2}{7}.\frac{13}{4}\)
\(=\frac{2}{7}.\left(\frac{21}{4}-\frac{13}{4}\right)\)
\(=\frac{2}{7}.\frac{8}{4}\)
\(=\frac{4}{7}\)
P/s: Mk ko chắc nữa!
-190 - x= -119 + 219 + 300
-190-x = 400
-x = 400 + 190
-x = 590
=> x = -590
Vậy...
\(a,30\cdot6+30\cdot71+20\cdot30\)
=\(30\cdot\left(6+71+20\right)\)
=\(30\cdot97=2910\)
\(b,24\cdot\left(31+119\right)+76\cdot\left(29+121\right)\)
=\(24\cdot150+76\cdot150\)
=\(150\cdot\left(24+76\right)\)
=\(150\cdot100\)
=\(15000\)
\(c,87\cdot23+70\cdot87+43\cdot93\)
=\(87\cdot\left(23+87\right)+43\cdot93\)
=\(87\cdot110+3999\)
=\(9570+3999\)
=13569
a) 15 . 6 . 2 + 3 . 71 . 10 + 20 . 30
= ( 15 . 2 ) . 6 + ( 3 . 10 ) . 71 + 20 . 30
= 30 . 6 + 30 . 71 + 20 . 30
= 30 . ( 6 + 71 + 30 )
= 30 . 107
= 3210
b) 24 . 31 + 24 . 119 + 76 . 29 + 76 . 121
= 24 . ( 31 + 119 ) + 76 . ( 29 + 121 )
= 24 . 150 + 76 . 150
= 150 . ( 24 + 76 )
= 150 . 100
= 15 000
c) 87 . 23 + 43 . 93 + 70 . 87
= 87 . 23 + 70 . 87 + 43 . 93
= 87 . ( 23 + 70 ) + 43 . 93
= 87 . 93 + 43 . 93
= 93 . ( 87 + 43 )
= 93 . 130
= 12 090
Sửa đề: 39*40
\(A=\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{12}+...+\dfrac{1}{39}-\dfrac{1}{40}=\dfrac{1}{5}-\dfrac{1}{40}=\dfrac{7}{40}\)
\(B=\dfrac{2}{3}\left(\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{17\cdot20}\right)\)
\(=\dfrac{2}{3}\left(\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+...+\dfrac{1}{17}-\dfrac{1}{20}\right)\)
=2/3*3/20=2/20=1/10=4/40<A
a, 119 + 24 + 81
= ( 119 + 81 ) + 24
= 200 + 24
= 224
b, 16 . 6 . 125
= 16 . 125 . 6
= 2000 . 6
= 12000
c, 25 . 104
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d, 12 . 19 + 12
= 12 . 19 + 12 . 1
= 12 . ( 19 + 1 )
= 12 x 20
= 240
e, 43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93 ) + ( 61 + 59 ) . 57
= 43 . 120 + 120 . 57
= 120 . 43 + 120 . 57
= 120 . ( 43 + 57 )
= 120 . 100
= 12000
a/ 199 + 24 + 81
= (119+81) + 24
= 200 + 24
= 224
b/ 16 . 6 . 125
= ( 16 . 125) . 6
= 2000 . 6
= 12000
c/ 25 . 104
= 25 . ( 100 + 4 )
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d/43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93) + 57 . ( 61+ 59)
= 43 . 130 + 57 . 130
= (43 + 57) . 130
= 100 . 130
= 1300
A = - [-806 - (-791) + 2012] - (806 - 1791)
A = 806 - 791 + 2012 - 806 + 1791
A = (806 - 806) + (1791 - 791)
A = 1000
B = 9 - (119).34 + 119.(-77) - (-119).11
B = 9 - 119(34 + 77 - 11)
B = 9 - 119.100
B = 9 - 11900
B = - 11891
a,
A=\(\left(2^9.16+2^8.24\right):2^{11}\)
A=\(\left(2^8.2.16+2^8.24\right):2^{11}\)
A=\(\left(2^8.32+2^8.24\right):2^{11}\)
A=\(\left[2^8.\left(32+24\right)\right]:2^{11}\)
A=\(\left(2^8.56\right):2^{11}\)
A=\(\left(2^8.8.7\right):2^{11}\)
A=\(\left(2^8.2^3.7\right):2^{11}\)
A=\(\left(2^{8+3}.7\right):2^{11}\)
A=\(\left(2^{11}.7\right):2^{11}\)
A=\(2^{11}.7:2^{11}\)
A=\(\left(2^{11}:2^{11}\right).7\)
A=\(1.7\)
A=\(7\)