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B1:
a)x=-3/5*9/25 =>x=-27/125
b)x=(4/7)6:(4/7)4 =>x=(4/7)2=16/49
c)(x/4)2=4:(x/2)
(x/4)2=8/x
x2/16=8/x2
x3=128
x=5,039
B2
M=23.10+22.10/23.4+22.11
=230+220/212+222
=230+28+222
=28(222+1+214)
=2

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^4+4^{10}.8^6}{8^4+4^{10}.4}\)
\(M=1\frac{8^6}{8^4+4^{10}.4}\)

\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)
\(=2^8=256\)
Mình không phải CTV nhưng có thể giúp bạn :)
Đừng dựa dẫm nhiều vào CTV nha bạn!
\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(=\frac{2^{20}×2^{10}+2^{20}}{2^{12}+2^{12}×2^{10}}\)
\(=\frac{2^{20}×\left(2^{10}+1\right)}{2^{12}×\left(1+2^{10}\right)}\)
\(=\frac{2^{20}}{2^{12}}=2^8\)
Cbht

\(A=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(A=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(A=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(A=\frac{4^{15}+4^{10}}{4^3+4^{11}}\)
\(A=\frac{4^{10}\left(4^5+1\right)}{4^6\left(4^5+1\right)}\)
\(A=\frac{4^{10}}{4^6}=4^4=256\)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)
\(M=\frac{2^{20}}{2^{12}}\)
\(M=\frac{2^{12}.2^8}{2^{12}}\)
\(M=2^8\)
M = 256
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8=256\)

a)\(\frac{2^{15}.3^2}{6^6.8^3.4}=\frac{2^{15}.3^2}{2^6.3^6.2^32^2}=\frac{2^{15}.3^2}{2^{\left(6+3+2\right)}.3^6}=\frac{2^{15}.3^2}{2^{11}.3^6}=\frac{2^{\left(15-11\right)}}{3^{\left(6-2\right)}}=\frac{2^3}{3^4}\) viết dài từng bước cho bạn dẽ hiểu
b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^{20-12}=2^8\)có thể đua về cơ số 4 thay cơ 2
- Bước 1: Rút gọn các phân số (nếu có thể)
- \(\frac{9}{6} = \frac{3}{2}\)
- \(\frac{6}{8} = \frac{3}{4}\)
- Bước 2: Thực hiện phép nhân
- \(\frac{2}{15} \cdot \frac{3}{2} = \frac{2 \cdot 3}{15 \cdot 2} = \frac{6}{30} = \frac{1}{5}\)
- \(\frac{3}{4} \cdot \frac{3}{4} = \frac{3 \cdot 3}{4 \cdot 4} = \frac{9}{16}\)
- Bước 3: Thực hiện phép cộng Vậy, \(\frac{2}{15} \cdot \frac{9}{6} + \frac{6}{8} \cdot \frac{3}{4} = \frac{61}{80}\)
- \(\frac{1}{5} + \frac{9}{16} = \frac{1 \cdot 16}{5 \cdot 16} + \frac{9 \cdot 5}{16 \cdot 5} = \frac{16}{80} + \frac{45}{80} = \frac{16 + 45}{80} = \frac{61}{80}\)
- Bước 1: Tính tử số
- \(\frac{8}{10} + \frac{4}{10} = \frac{8 + 4}{10} = \frac{12}{10} = \frac{6}{5}\)
- Bước 2: Tính mẫu số
- \(\frac{8}{4} + \frac{4}{11} = 2 + \frac{4}{11} = \frac{2 \cdot 11}{11} + \frac{4}{11} = \frac{22}{11} + \frac{4}{11} = \frac{22 + 4}{11} = \frac{26}{11}\)
- Bước 3: Thực hiện phép chia Vậy, \(\frac{\frac{8}{10} + \frac{4}{10}}{\frac{8}{4} + \frac{4}{11}} = \frac{33}{65}\)
- \(\frac{\frac{6}{5}}{\frac{26}{11}} = \frac{6}{5} : \frac{26}{11} = \frac{6}{5} \cdot \frac{11}{26} = \frac{6 \cdot 11}{5 \cdot 26} = \frac{66}{130} = \frac{33}{65}\)
- a) \(\frac{61}{80}\)
- b) \(\frac{33}{65}\)
- tick mik với bn

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)
Chúc học tốt :)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)
\(M=\frac{2^{20}}{2^{12}}\)
\(M=2^8=256\)
\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)
Vậy
\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)
P/s; Ko chắc đâu nhé
8^10+4^10/8^4+4^11=(2.4)^10+4^10/(2.4)^4+4^11
=2^10.4^10+4^10/2^4.4^4+4^11=4^10.(2^10+1)/(2^2)^4.4^4+4^11
=4^10.(2^10+1)/4^12+4^11
=4^10.(2^10+1)/4^11.(4+1)=2^10+1/4.5=1025/20=205/4