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a: =>|5/4x-7/2|=|5/8x+3/5|
=>5/4x-7/2=5/8x+3/5 hoặc 5/4x-7/2=-5/8x-3/5
=>5/8x=41/10 hoặc 15/8x=29/10
=>x=164/25 hoặc x=116/75
b: =>3:|x/4-2/3|=6-21/5=9/5
=>|1/4x-2/3|=5/3
=>1/4x-2/3=5/3 hoặc 1/4x-2/3=-5/3
=>1/4x=7/3 hoặc 1/4x=-1
=>x=28/3 hoặc x=-4
c: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(2x-x-9\right)\left(2x+x+9\right)=0\end{matrix}\right.\Leftrightarrow x=9\)
e: =>|2x-7|=2x-7
=>2x-7>=0
=>x>=7/2
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
a) -1/24 - [ 1/4 - ( 1/2 - 7/8 )]
= -1/24 - [ 1/4 +3/8 ]
= -1/24 - 5/8
= -2/3.
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
A=(1+3+5+7+..+2017).(2/3:(-0.75)-0.25:(-3,5/9):(-1-1/3-1/5-1/7-...-1/2017)
Cái (-3,5/9) là hỗn số nha
\(\left(\frac{2}{5}\right)^6:\left(\frac{2}{5}\right)^4=\left(\frac{2}{5}\right)^2=\frac{4}{25}\)
\(\left(\frac{3}{16}\right)^2:\left(\frac{9}{8}\right)^2=\frac{1}{12}\)
\(\left(\frac{2}{7}-\frac{1}{2}\right)^2=\frac{9}{196}\)
A : 3 - 2 = -x + 1/7
1 = -x + 1/7
x= 1/7 -1
x = -6/7
B: 4/5 + (-1/9) = 8/7 -x
31/45 = 8/7 -x
x= 8/7 -31/45
x=143/315
C: [x-1/3] =10
=> 10\(\le\)3x-1/3 \(< \)11
=> 30 \(\le\)3x-1 \(< \)33
=> 31\(\le3x\)<34
<=> 11\(\le x< 12\)
=> x=11
D: [ -x + 2/5 ] = 3,5 -1/2
[-5x+2/5]=3
=> 3\(\le\)-5x+2/5 <4
=> 15\(\le\)-5x+2 <20
=> 13\(\le\)-5x< 18
=> -3\(\ge\)x>-4
=> x = -3
a) \(...-\dfrac{22}{7}:-\dfrac{15}{9}=\dfrac{22}{7}.\dfrac{9}{15}=\dfrac{66}{35}\)
b) \(...\dfrac{8}{3}:\left(-\dfrac{42}{7}\right)=\dfrac{8}{3}.\left(-\dfrac{7}{42}\right)=-\dfrac{8}{9}\)
c) ...\(\left(-\dfrac{7}{2}\right):\left(-\dfrac{13}{5}\right)=\dfrac{7}{2}.\dfrac{5}{13}=\dfrac{35}{36}\)