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a) \(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)
0,5 x + 0,6 ( x - 2 ) = 3
0,5 x + 0.6 x - 1,2 = 3
1,1 x = 4,2
x = \(\frac{42}{11}\)
Kết luận:
b) \(\frac{1}{3}x-0,5x=0,75\)
\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)
\(-\frac{1}{6}x=\frac{3}{4}\)
\(x=-\frac{9}{2}\)
Kết luận:
c) \(\frac{3}{-2}x-0,5x=75\%\)
-1,5x - 0,5x = 0,75
-2x = 0,75
x = -0,375
Kết luận:
d) \(-\frac{2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)
-0,4 x + 0,25 = 0,75 - 0,75 x
-0,4 x + 0,75 x = 0,75 - 0,25
0,35 x = 0,5
x = \(\frac{10}{7}\)
Kết luận:
\(a,\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)
\(\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)
\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)
\(\frac{11}{10}x-\frac{6}{5}=3\)
\(\frac{11}{10}x=\frac{21}{5}\)
\(x=\frac{42}{11}\)
\(b,\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)
\(\left(\frac{1}{3}-\frac{1}{2}\right)x=\frac{3}{4}\)
\(\frac{-1}{6}x=\frac{3}{4}\)
\(x=\frac{-9}{2}\)
\(c,\frac{3}{-2}x-\frac{1}{2}x=75\%\)
\(\left(\frac{3}{-2}-\frac{1}{2}\right)x=\frac{3}{4}\)
\(-2x=\frac{3}{4}\)
\(x=\frac{-3}{8}\)
\(\frac{-2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)
\(\frac{-2}{5}x+\frac{3}{4}x=\frac{3}{4}-\frac{1}{4}\)
\(\left(\frac{-2}{5}+\frac{3}{4}\right)x=\frac{1}{2}\)
\(\frac{7}{20}x=\frac{1}{2}\)
\(x=\frac{10}{7}\)
\(\frac{1}{3}.x+\frac{3}{4}.x-75\%=-\frac{21}{4}\)
\(\frac{1}{3}.x+\frac{3}{4}.x-\frac{3}{4}=-\frac{21}{4}\)
\(x.\left(\frac{1}{3}+\frac{3}{4}\right)=-\frac{21}{4}+\frac{3}{4}\)
\(x.\frac{13}{12}=-\frac{9}{2}\)
\(x=-\frac{9}{2}:\frac{13}{12}\)
\(x=-\frac{54}{13}\)
=> x.(1/3+3/4) -75/100=-21/4
=> x .13/12 - 3/4 =21/4
=> x. 13/12 =21/4 + 3/4
=> x.13/12 =6
=> x = 6 : 13/12
=> x = 72/13
vậy x= 72/13
\(\frac{1}{3}.x+\frac{3}{4}.x-75\%=\frac{-51}{4}\)
\(x.\left(\frac{1}{3}+\frac{3}{4}\right)-\frac{3}{4}=\frac{-51}{4}\)
\(x.\left(\frac{4}{12}+\frac{9}{12}\right)=\frac{-51}{4}+\frac{-3}{4}\)
\(x.\frac{13}{12}=\frac{-54}{4}=\frac{-27}{2}\)
\(x=\frac{-27}{2}:\frac{13}{12}=\frac{-27}{2}.\frac{2}{13}=\frac{-27.2}{2.13}=\frac{-27.1}{1.13}=\frac{-27}{13}\)
Xin lỗi cho mình sửa lại
\(\frac{1}{3}.x+\frac{3}{4}.x-75\%=\frac{-51}{4}\)
\(x.\left(\frac{1}{3}+\frac{3}{4}\right)-\frac{3}{4}=\frac{-51}{4}\)
\(x.\left(\frac{4}{12}+\frac{9}{12}\right)=\frac{-51}{4}+\frac{3}{4}=\frac{-48}{4}\)
\(x.\frac{13}{12}=-12\)
\(x=-12:\frac{13}{12}=12.\frac{12}{13}=\frac{-12.12}{13}=\frac{-144}{13}\)
a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
a, 7\(x\) - \(x\) = 521 : 519 + 3.22.7
6\(x\) = 53 + 3.4.7
6\(x\) = 125 + 12.7
6\(x\) = 125 + 84
6\(x\) = 209
\(x\) = 209 : 6
\(x\) = \(\dfrac{209}{6}\)
b; 11\(x\) - 7\(x\) + 34 : 33 = 54 + 2\(x\)
4\(x\) + 3 = 625 + 2\(x\)
4\(x\) - 2\(x\) = 625 - 3
2\(x\) = 622
\(x\) = 622 : 2
\(x\) = 311
c; 75 - 5.(\(x-3\))3 = 700
5.(\(x\) - 3)3 = 700 - 75
5.(\(x\) - 3)3 = - 625
(\(x\) - 30)3 = - 625 : 5
(\(x\) - 30)3 = - 125
(\(x-3\))3 = (-5)3
\(x\) - 3 = - 5
\(x\) = - 5 + 3
\(x\) = -2
d, 3.(2\(x\) - 1)2 = 75
(2\(x\) - 1)2 = 75 : 3
(2\(x\) - 1)2 = 25
\(\left[{}\begin{matrix}2x-1=-5\\2x-1=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-5+1\\2x=5+1\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-4\\2x=6\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)
c) Ta có: \(\left|x-\dfrac{2}{3}\right|+2.25=\dfrac{3}{4}\)
\(\Leftrightarrow\left|x-\dfrac{2}{3}\right|=\dfrac{3}{4}-\dfrac{9}{4}=\dfrac{-3}{2}\)(vô lý)
Vậy: \(x\in\varnothing\)
a) Ta có: \(x+\dfrac{-3}{7}=\dfrac{4}{7}\)
\(\Leftrightarrow x-\dfrac{3}{7}=\dfrac{4}{7}\)
hay x=1
Vậy: x=1
Bài 1:
a) =25,97+(6,54+103,46)
=25,97+110
=135,97
b)136x75+75x64
=75x(136+64)
=75x200
=15 000
c) (21/8+1/2):5/16
=(21/8+4/8)x16/5
=25/8x16/5
=10
d)3/17-4/5+14/17
=(3/17+14/17)-4/5
=1-4/5
=1/5
Bài 2:
a)720:\([41-(2x-5)]\)=120
41 - (2x-5) =720:120
41 - (2x-5) =6
2x-5 =41-6
2x-5 =35
2x =35+5
2x =40
x =40:2
x =20
b)2/3 x X +3/4=3
2/3 x X =3-3/4
2/3 x X =12/4-3/4
2/3 x X =9/4
x =9/4:2/3
x =9/4x3/2
x =27/8
c) x+0,34=1,19x1,02
x+0,34=1,2138
x =1,2138-0,34
x =0,8738
\(\left(3\dfrac{3}{4}\times x+75\%\right):\dfrac{2}{3}=-1\)
\(\Rightarrow\dfrac{15}{4}\times x+\dfrac{3}{4}=-\dfrac{2}{3}\)
\(\dfrac{15}{4}\times x=-\dfrac{2}{3}-\dfrac{3}{4}\)
\(\dfrac{15}{4}\times x=-\dfrac{17}{12}\)
\(x=-\dfrac{17}{12}:\dfrac{15}{4}\)
\(x=-\dfrac{17}{45}\)
\(75\%x-x=1-\frac{3}{4}\)
\(\Rightarrow\frac{75}{100}.x-x=\frac{1}{4}\)
\(\Rightarrow\frac{3}{4}x-x=\frac{1}{4}\)
\(\Rightarrow x.\left(\frac{3}{4}-1\right)=\frac{1}{4}\)
\(\Rightarrow x.\frac{-1}{4}=\frac{1}{4}\)
\(\Rightarrow x=-1\)