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2 tháng 10 2016

\(\frac{6x-5}{-7}=\frac{5x-3}{-5}\)


(6x-5)-5 = (5x-3)-7

-30x+25 = -35x+21

-30x+35x = 21-25

x(-30+35) = -4

5x = -4

x =\(\frac{-4}{5}\)

1 tháng 8 2016

\(6x-\frac{5}{-7}=5x-\frac{3}{-5}\)

<=>6x-5x=-5/7-(-3/5)

<=>x=-4/35

đúng đi :))

22 tháng 9 2018

* Trả lời:

\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)

\(\Leftrightarrow-3+6x-4-12x=-5x+5\)

\(\Leftrightarrow6x-12x+5x=3+4+5\)

\(\Leftrightarrow x=12\)

\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)

\(\Leftrightarrow6x-15-6+24x=-3x+7\)

\(\Leftrightarrow6x+24x+3x=15+6+7\)

\(\Leftrightarrow33x=28\)

\(\Leftrightarrow x=\dfrac{28}{33}\)

\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)

\(\Leftrightarrow1-3x-6x+12=-4x-5\)

\(\Leftrightarrow-3x-6x+4x=-1-12-5\)

\(\Leftrightarrow-5x=-18\)

\(\Leftrightarrow x=\dfrac{18}{5}\)

\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)

\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)

\(\Leftrightarrow-x-5x=-7\)

\(\Leftrightarrow-6x=-7\)

\(\Leftrightarrow x=\dfrac{7}{6}\)

\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)

\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)

\(\Leftrightarrow-15x+3x=4\)

\(\Leftrightarrow-12x=4\)

\(\Leftrightarrow x=-\dfrac{1}{3}\)

15 tháng 7 2021

a) 6x(5x + 3) + 3x(1 – 10x) = 7  

⇒ 30x2+18x+3x-30x2=7

⇒21x=7

⇒x=\(\dfrac{7}{21}\)

⇒x= \(\dfrac{1}{3}\)

 

15 tháng 7 2021

b) (3x – 3)(5 – 21x) + (7x + 4)(9x – 5) = 44

⇒15x-63x2-15+63x + 63x2-35x+36x-20=44

⇒79x-35=44

⇒79x=44+35

⇒79x=79

⇒x=1

a: \(\Leftrightarrow12x^2-10x-12x^2-28x=7\)

=>-38x=7

hay x=-7/38

b: \(\Leftrightarrow-10x^2-5x+9x^2+6x+x^2-\dfrac{1}{2}x=0\)

=>1/2x=0

hay x=0

c: \(\Leftrightarrow18x^2-15x-18x^2-14x=15\)

=>-29x=15

hay x=-15/29

d: \(\Leftrightarrow x^2+2x-x-3=5\)

\(\Leftrightarrow x^2+x-8=0\)

\(\text{Δ}=1^2-4\cdot1\cdot\left(-8\right)=33>0\)

Do đó: Phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{-1-\sqrt{33}}{2}\\x_2=\dfrac{-1+\sqrt{33}}{2}\end{matrix}\right.\)

e: \(\Leftrightarrow-15x^2+10x-10x^2-5x-5x=4\)

\(\Leftrightarrow-25x^2=4\)

\(\Leftrightarrow x^2=-\dfrac{4}{25}\left(loại\right)\)

17 tháng 9 2017

\(\frac{6x-5}{-7}=\frac{3-5x}{5}\Leftrightarrow5\left(6x-5\right)=-7\left(3-5x\right)\Leftrightarrow30x-25=-21+35x\)

\(\Leftrightarrow-5x=4\Leftrightarrow x=-\frac{4}{5}\)

a: =3x^3-15x^2+21x

b: =-x^3+6x^2+5x-4x^2-24x-20

=-x^3+2x^2-19x-20

c: =9x^2+15x-3x-5-7x^2-14

=2x^2+12x-19

d: =10x^2-4x+2/3

29 tháng 8 2016

b)

\(\frac{x-1}{x-5}=\frac{6}{7}\)

\(\Rightarrow\left(x-1\right)7=\left(x-5\right)6\)

\(\Rightarrow7x-7=6x-30\)

\(\Rightarrow7x-6x=-30+7\)

\(\Rightarrow x=-23\)

c)

\(\frac{\left(6x-5\right)}{-7}=\frac{5x-3}{-5}\)

\(\Rightarrow\left(6x-5\right)\left(-5\right)=\left(5x-3\right)\left(-7\right)\)

\(\Rightarrow25-30x=21-35x\)

\(\Rightarrow-30x+35x=21-25\)

\(\Rightarrow5x=-4\)

\(\Rightarrow x=-\frac{4}{5}\)

23 tháng 10 2021

\(\dfrac{6x+5}{5x-3}=\dfrac{38-6x}{21-5x}\left(đk:x\ne\dfrac{5}{3},x\ne\dfrac{21}{5}\right)\)

\(\Rightarrow\left(6x+5\right)\left(21-5x\right)=\left(5x-3\right)\left(38-6x\right)\)

\(\Rightarrow-30x^2+101x+105=-30x^2+208x-114\)

\(\Rightarrow107x=219\Rightarrow x=\dfrac{219}{107}\left(tm\right)\)

23 tháng 10 2021

\(\dfrac{6x+5}{5x-3}=\dfrac{6x-38}{5x-21}\)

\(\Leftrightarrow30x^2-126x+25x-105=30x^2-18x-190x+114\)

\(\Leftrightarrow-101x-105=-208x+114\)

\(\Leftrightarrow107x=219\)

hay \(x=\dfrac{219}{107}\)