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\(\left(5x+2\right)+\left(5x+4\right)+\left(5x+6\right)+...+\left(5x+200\right)=90100.\)
\(\Leftrightarrow5x+2+5x+4+5x+6+...+5x+200=90100\)
\(\Leftrightarrow\left(5x+5x+...+5x\right)+\left(2+4+6+...+200\right)=90100\)
\(\text{Số các số hạng là: }\frac{\left(200-2\right)}{2}+1=100\left(\text{số}\right)\text{ *Chú ý chỗ nãy nếu lớp 7-8 rồi thì ko cần }\)
\(\Leftrightarrow5x.100+\frac{\left(200+2\right).100}{2}=90100\)
\(\Leftrightarrow500x+10100=90100\)
\(\Leftrightarrow x=\frac{90100-10100}{500}\)
\(\text{Vậy }x=160\)
X2x—7=15
2x=15+7
2x=22
x=22:2
x=11
4x +5=205
4x=205–5
4x=200
x=200:4
x=50
80/(x+1)=40
==> 80: x+1=40
80:x=40-1
80:x=39
x=80:39
x=80/39
72–(2x—4)=2
2x—4=72-2
2x—4=70
2x=70+4
2x=74
x=74:2
x=37
75-5(x+3)=5
5(x+3)=75–5
5(x+3)=70
x+3=70:5
x+3=14
x=14–3
x=11
7x:7=4
7x=4.7
7x=28
x=28:7
x=4
20:(x—5)=20
x—5=20:20
x—5=1
x=1+5
x=6
9(2x—8)=0
2x=0:9
2x=0
x=0:2
x=0
2080:4x=40
4x=2080:40
4x=52
x=52:4
x=13
A tính theo công thức tính tổng dãy số cách đều có khoảng cách là 3 (cấp số cộng có d=3)
\(3C=2x3x3+3x4x3+4x5x3+5x6x3+...x199x200x3+200x201x3\)
\(3C=2x3x\left(4-1\right)+3x4x\left(5-2\right)+4x5x\left(6-3\right)+...+200x201\left(202-199\right)\)
3C=--1x2x3+2x3x4-2x3x4+3x4x5-3x4x5+4x5x6-...-199x200x201+200x201x202
3C=200x201x202-1x2x3=> C=(200x201x202-1x2x3):3=200x67x202-2
a) \(2^x.4=128\Rightarrow2^x=32=2^5\Rightarrow x=5\)
b) \(x^{17}=x\Rightarrow x^{17}-x=0\Rightarrow x\left(x^{16}-1\right)=0\Rightarrow x=0\) hay \(x=1\)
c) \(\left(2x-2\right)^3=8\Rightarrow\left(2x-2\right)^3=2^3\Rightarrow2x-2=2\Rightarrow2x=4\Rightarrow x=2\)
d) \(\left(x-6\right)^3=\left(x-6\right)^2\Rightarrow\left(x-6\right)^3-\left(x-6\right)^2=0\)
\(\Rightarrow\left(x-6\right)^2\left(x-6-1\right)=0\Rightarrow\Rightarrow\left(x-6\right)^2\left(x-7\right)=0\)
\(\Rightarrow x-6=0\) hay \(x-7=0\Rightarrow x=6\) hay \(x=7\)
e) \(\left(7x-11\right)^3=2^5.5^2+200\Rightarrow\left(7x-11\right)^3=32.25+200\)
\(\Rightarrow\left(7x-11\right)^3=1000=10^3\Rightarrow7x-11=10\Rightarrow7x=21\Rightarrow x=3\)
f) \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\Rightarrow2^{x-1}=24-\left[16-3\right]-3\)
\(\Rightarrow2^{x-1}=24-13-3\Rightarrow2^{x-1}=8=2^3\Rightarrow2x-1=3\Rightarrow2x=4\Rightarrow x=2\)
a: =>4x-5=0 hoặc 5/4x-2=0
=>x=5/4 hoặc x=2:5/4=2*4/5=8/5
b: =>(1/12+19/6-30,75)*x-8=102
=>-55/2x=110
=>x=-4
\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
( 5 . x + 2 ) + ( 5 . x + 4 ) + ( 5 . x + 6 ) + .... + ( 5 . x + 200 ) = 90100
- Số số hạng vế trái là : [ ( 5x + 200 ) - ( 5x + 2 ) ] :2 + 1 = 100 ( số hạng )
=> [ ( 5x + 2 ) + ( 5x + 200 ) ] x 100 : 2 = 90100
=> [ ( 5x + 2 ) + ( 5x + 200 ) ] x 100 = 180200
=> [ ( 5x + 2 ) + ( 5x + 200 ) ] = 1802
=> 5x . 2 + 202 = 1082
=> 5x . 2 = 1600
=> 5x = 800
=> x = 160
x=160 nha
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