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=9x2^25-2^2x2^26/2^24x5^2-2^27x3
=9x2^25-2^28/2^24x5^2-2^27x3
=2^25x(9-2^3)/2^24x(5^2-2^3x3)
=2^25/2^24
=2^1=2
a)4^x=64
4^x=4^3
<=>x=3
b)3^x-1=27
3^x-1=3^3
<=>x-1=3
x=3+1
x=4
c)26+8x-6x=46
26+x(8-6)=46
26+2x=46
2x=46-26
2x=20
x=20:2
x=10
d)\(25\le5^x\le625\)
<=>\(5^2\le5^x\le5^4\)
<=>\(2\le x\le4\)
<=>\(x\in\left\{2;3;4\right\}\)
e)10+2x=4^5:4^3
10+2x=4^5-3
10+2x=4^2
10+2x=16
2x=16-10
2x=6
x=6:2
x=3
a) 4x = 64
\(\Rightarrow\)4x = 43
\(\Rightarrow\)x = 3
b) 3x - 1 = 27
\(\Rightarrow\)3x - 1 = 33
\(\Rightarrow\)x - 1 = 3
\(\Rightarrow\)x = 4
c) 26 + 8x - 6x = 46
\(\Rightarrow\)26 + 2x = 46
\(\Rightarrow\)2x = 46 - 26
\(\Rightarrow\)2x = 20
\(\Rightarrow\)x = 10
d) 25 \(\le\)5x \(\le\)625
\(\Rightarrow\)52\(\le\)5x\(\le\)54
\(\Rightarrow\)x \(\in\){ 2 ; 3 ; 4 }
e) 10 + 2x = 45 : 43
\(\Rightarrow\)10 + 2x = 42 = 16
\(\Rightarrow\)2x = 16 - 10
\(\Rightarrow\)2x = 6
\(\Rightarrow\)x = 3
\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\left(x+\dfrac{1}{5}\right)^2=\left(\dfrac{3}{5}\right)^2\)
➩ \(x+\dfrac{1}{5}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}-\dfrac{1}{5}\)
\(x=\dfrac{2}{5}\)
\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
đáp án : x = 2
giải thích các bước giải
5^25 . 5^x-1 = 5^26
áp dụng công thức : a^n . a^m = a^n + m
----> ta có : 25 + ( x - 1 ) = 26
x - 1 = 26 - 25 = 1
x = 1 + 1 = 2
Tl
= X = 2
Hok tốt