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`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}+\left[\dfrac{4}{5}x-\dfrac{11}{15}\right]=\dfrac{5}{9}\)
`=>`\(\dfrac{4}{5}x-\dfrac{11}{15}=\dfrac{5}{9}-\dfrac{2}{3}\)
`=>`\(\dfrac{4}{5}x-\dfrac{11}{15}=-\dfrac{1}{9}\)
`=>`\(\dfrac{4}{5}x=-\dfrac{1}{9}+\dfrac{11}{15}\)
`=>`\(\dfrac{4}{5}x=\dfrac{28}{45}\)
`=>`\(x=\dfrac{28}{45}\div\dfrac{ 4}{5}\)
`=>`\(x=\dfrac{7}{9}\)
Vậy, `x = 7/9.`
\(\left(\dfrac{3}{4}-3x\right)\cdot\left(1+4x\right)=0\)
`=>`\(\left[{}\begin{matrix}\dfrac{3}{4}-3x=0\\1+4x=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}3x=\dfrac{3}{4}\\4x=-1\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)
Vậy, `x \in {1/4; -1/4}.`
Sửa đề: \(\left(4x+15\cdot3\right)-11=-2^4\)
=>\(4x+35-11=-16\)
=>4x+24=-16
=>4x=-14-26=-40
=>x=-40/4=-10
1.a) 4.(12+88) = 4.100=400
b)72- 6 .[2.8:8 ]=72-6.[16:8]=72-6 .2= 49-12=37 ( tui ko chắc lắm )
2.a) x=26-11=15
b) (4x-15)3=53
4x-15=5
4x= 5+15
4x=20
vậy x = 20
Bài 2:
a: Ta có: x+11=26
nên x=15
b: Ta có: \(\left(4x-15\right)^3=125\)
\(\Leftrightarrow4x-15=5\)
hay x=5
\(\text{2^5.3 - 3.(x+1)=42}\)
\(3\left(x+1\right)=54\)
\(x+1=18\)
\(x=17\)
\(\text{(4x + 5) : 3 - 11^2:11=2^2}\)
\((4x+5):3-11=4\)
\((4x+5):3=15\)
\((4x+5)=5\)
\(4x=0\)
\(x=0\)
\(\text{3x - 15 . 4 = 6.(19 - x)}\)
\(\text{3x - 60 = 6.(19 - x)}\)
\(\text{3x - 60 :(19-x)= 6}\)
\(\Rightarrow x=6\)
\(\text{(x - 7).(2x - 16)=0}\)
\(\Rightarrow\hept{\begin{cases}x-7=0\\2x-16=0\end{cases}\Rightarrow\hept{\begin{cases}x=7\\8\end{cases}}}\)
a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)
- 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50
2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51
7\(x\) = 67
\(x\) = 67 : 7
\(x\) = \(\dfrac{67}{7}\)
Vậy \(x\) = \(\dfrac{67}{7}\)
b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)
17\(x\) - 48\(x\) - 111 = 2\(x\) - 4\(x\) + 43
- 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43
- \(x\) x (31 + 2 - 4) = 154
- \(x\) x (33 - 4) = 154
- \(x\) x 29 = 154
- \(x\) = 154 : (-29)
\(x\) = - \(\dfrac{154}{29}\)
Vậy \(x=-\dfrac{154}{29}\)
a) x – 32 : 16 = 48 ó x – 2 = 48 ó x = 48 + 2 ó x = 50
b) 88 – 3.(7+x) = 64 ó 3.(7+x) = 88 – 64 ó 7 + x = 24:3 ó x = 8 – 7 ó x = 1
c) (5+4x) : 3 – 121 : 11 = 4 ó (5+4x) : 3 – 11 = 4 ó (5+4x) : 3 = 4 + 11 ó 5+4x = 15.3 ó 4x = 45 – 5 ó 4x = 40 ó x = 10
d) 15 – 2(3x+1) = 11.13 – 130 ó 15 – 2(3x+1) = 143 – 130 ó 15 – 2(3x+1) = 13
ó 2(3x+1) = 15 – 13 ó 3x + 1 = 2:2 ó 3x = 1 – 1 ó 3x = 0 ó x = 0
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`=>` `x = 11`
\(\left(4x+15\right)^3=27\Rightarrow4x+15=3\Leftrightarrow x=-3\)
(4x + 15)3- 11 = ( - 2 )4
(4x + 15)3 = (-2)4+11
(4x + 15)3 = 27
(4x+15)3 = 33
=> 4x+15 = 3
4x = -12
x = -3