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\(4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{40-15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=\frac{2^{20}}{2^{18}}=2^2=4\)
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S = 5 + 52 + 53 + ... + 52012
5S = 52 + 53 + 54 + ... + 52013
5S - S = [52 + 53 + 54 + ... + 52013]- [5 + 52 + 53 + ... + 52012]
4S = 52013 - 5
\(S=\frac{5^{2013}-5}{4}\)
5S= 5^2+5^3+5^4+... +5^2013
=>4S=(5^2+5^3+5^4+... +5^2013) -(5+5^2+... +5^2012)
=>4S=5^2013-5
=>S=(5^2013-5) :4
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Tìm n:
2^n+3 + 2^n = 144
=> 2^n . 2^3 + 2^n = 144
=> 2^n . ( 2^3 + 1 ) = 144
=> 2^n . 9 = 144
=> 2^n = 144 : 9
=> 2^n = 16
=> 2^n = 2^4
=> n = 4
Vậy n = 4
Có gì ko hiểu bn ib mk nha ^^
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\(4^{\left(100-1\right):1+1.\left(100+1\right):2}\)
\(4^{100.101:2}\)
\(4^{10100:2}\)
\(4^{5050}\)
mk ko chắc là đúng hay ko
4.42 . 43 . 44 . 45 .... . 4 98 . 499 . 4 100
Số số hạng : ( 100 - 1 ) : 1 + 1 = 100
Tổng : ( 100+1 ) . 100 : 2 = 5050
Vậy số đó là : 45050
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=>3B=3^2+3^3+3^4+...+3^2006
=>3B-B=3^2006-3
=>2B=3^2006-3
=>2B+3=3^2006
**** cho mik nha!
B = 3 + 32 + ... + 32005
3B = 32 + 33 + ... + 32006
3B - B = 32006 - 3
2B = 32006 - 3
=> 32006 - 3 + 3 = 32006
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( 20 . 24 + 12 . 24 - 48 . 22 ) : 26
= (5.22. 24 + 3.22 . 24 - 3. 24 . 22):26
= ( 5. 26 +3.26- 3.26) :26
= 26( 5+3-3):26
= 26.5:26
= 5
( 20 . 24 + 12 . 24 - 48 . 22 ) : 26
= [24 .(20 + 12) - 48 . 22] : 26
= [24 . 32 - 48 . 22] : 26
= [22 . 22 . 25 - 48 . 22] : 26
= [22 . 27 - 48 . 22] : 26
= [22 . (27 - 48)] : 26
= [22 . (128 - 48)] : 26
= [4 . 80] : 64
= 320 : 64
= 5
\(4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=2^{20}:2^{18}=2^2\)
\(4^{20}\)\(:2^{15}\)\(=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{40-15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=2^{20}:2^{18}=2^{20-18}=2^2\)