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\(4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=2^{20}:2^{18}=2^2\)
\(4^{20}\)\(:2^{15}\)\(=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{40-15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=2^{20}:2^{18}=2^{20-18}=2^2\)
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S = 5 + 52 + 53 + ... + 52012
5S = 52 + 53 + 54 + ... + 52013
5S - S = [52 + 53 + 54 + ... + 52013]- [5 + 52 + 53 + ... + 52012]
4S = 52013 - 5
\(S=\frac{5^{2013}-5}{4}\)
5S= 5^2+5^3+5^4+... +5^2013
=>4S=(5^2+5^3+5^4+... +5^2013) -(5+5^2+... +5^2012)
=>4S=5^2013-5
=>S=(5^2013-5) :4
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a125^5:25^3=(5^3)^5:(5^2)^3=5^15:5^6=5^9
b27^6:9^3=(3^3)^6:(3^2)^3=3^18:3^6=3^13
c 4^20:2^15=(2^2)^20:2^15=2^40:2^15=2^25
d24^n:2^2.n=24^n:(2^2)^n=24^n:4^n=(24:4)^n=6^n
e 64^4 . 16^5:4^20=(2^6)^4 . (2^4)^5 :(2^2)^20=2^24 . 2^20:2^40=2^4
g 32^4:8^6=(2^5)^4:(2^3)^6=2^20:2^18=2^2
a, \(125^5:25^3=\left(5^3\right)^5:\left(5^2\right)^3=5^{15}:5^6=5^9\)
b, \(27^6:9^3=\left(3^3\right)^6:\left(3^2\right)^3=3^{18}:3^6=3^{12}\)
c, \(4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{25}\)
d, \(24^n:2^{2.n}=2^n.12^n:2^n.2^n=12^n:2^n=2^n.6^n:2^n=6^n\)
e, \(64^4.16^5:4^{20}=4^{12}.4^{10}:4^{20}=4^{12+10-20}=4^2\)
g, \(32^4:8^6=8^4.4^4:8^4.8^2=4^4:4^2.2^2=4^2.2^2=2^4.2^2=2^6\)
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12x-4^3.8^3=2^2.(2^2)^3
12x.(2^2)^3.(2^3)^3=2^2.2^6
12x-2^6.2^9=2^8
12x-2^15=2^8
12x=2^8+2^15
12x=256+32768
12x=33024
x=33024/12
x=2752
cam on bn
bn co de thi toan lop 6 1 tiet ko cho mik xem nhe
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a)a là số có 1 chữ số mà a-4=4=>a=4+4=8
=>785b1 chia hết cho 3
=>7+8+5+1+b chia hết cho 3
=>21+b chia hết cho 3
=>b={0;3;6;9}
Vậy a=8 b={0;3;6;9}
Chung m ran a thuoc z thi a(a+2) - a(a-5)-7 a boi cua 7
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( 20 . 24 + 12 . 24 - 48 . 22 ) : 26
= (5.22. 24 + 3.22 . 24 - 3. 24 . 22):26
= ( 5. 26 +3.26- 3.26) :26
= 26( 5+3-3):26
= 26.5:26
= 5
( 20 . 24 + 12 . 24 - 48 . 22 ) : 26
= [24 .(20 + 12) - 48 . 22] : 26
= [24 . 32 - 48 . 22] : 26
= [22 . 22 . 25 - 48 . 22] : 26
= [22 . 27 - 48 . 22] : 26
= [22 . (27 - 48)] : 26
= [22 . (128 - 48)] : 26
= [4 . 80] : 64
= 320 : 64
= 5
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4.x10-9.x8=0
=>x8.(4x2-9)=0
=>x8=0 hoặc 4x2-9=0
=>x=0 hoặc x=3/2
Vậy x=0 hoặc x=3/2
\(4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40}:2^{15}=2^{40-15}=2^{25}\)
\(32^4:8^6=\left(2^5\right)^4:\left(2^3\right)^6=\frac{2^{20}}{2^{18}}=2^2=4\)
420: 215
= (4:2) 20-15
= 25
324:86
= 1048576 : 262144
= 4