Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(2^2+4^2+6^2+...+20^2\)
\(=2^2\left(1+2^2+3^2+...+10^2\right)\)
\(=4\cdot385=1540\)
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
22+42+62+...+202
=22.(1+22+32+...+102)
=4.\(\frac{10.\left(10+1\right)\left(2.10+1\right)}{6}\)(công thức tính tổng các bình phương liên tiếp)
=4.385
=1540
\(2^2\) \(_+\) \(4^2\) \(+\)\(6^2\) \(+\) \(...+\)\(20^2\)\(=1540\)
\(S=2^2+4^2+6^2+...+20^2\)
\(S=\left(2.1\right)^2+\left(2.2\right)^2+\left(2.3\right)^2+...+\left(2.10\right)^2\)
\(S=2^2.1^2+2^2.2^2+2^2.2^3+...+2^2.10^2\)
\(S=2^2\left(1^2+2^2+3^2+...+10^2\right)\)
\(S=2^2.385\)
\(S=4.385\)
\(S=1540\)
A = \(2^2.\left(1^2+2^2+3^2+...+10^2\right)=4.385=1540\)
B=\(3^2.\left(1^2+2^2+3^2+...+10^2\right)=385.9=3465\)