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a, 15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0
= 15.{32:[1+15]+3}–1
= 15.5–1
= 74
b, 25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }
= 25.{128:[8+4.2]–16}
= 25.24
= 600
c, 2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }
= 2019.{101–1000:[(32+125–36):11–1]}
= 2019.{101–1000:[121:11–1]}
= 2019.{101–1000:10}
= 2019.1
= 2019

\(a,157.17-157.7=157\left(17-7\right)=1570\)
\(b,5.\left(-3+2\right)-7.\left(5-4\right)=-5-7=-12\)
\(c,17.\left(-84\right)+17\left(-16\right)=17\left[\left(-84\right)+\left(-16\right)\right]=-1700\)
\(d,-145.\left(13-57\right)+57.\left(10-145\right)=6380-7695=-1315\)
\(e,199.\left(15-17\right)-199.\left(-17+5\right)=199.10=1990\)

x - (40 - 67) = 2018⁰
x - (-27) = 1
x + 27 = 1
x = 1 - 27
x = -26
\(x\) - (40 - 67) = 20180
\(x\) + (67 - 40) = 1
\(x\) + 27 = 1
\(x\) = 1 - 27
\(x\) = - 26

Ta có : \(\left|-3-5\right|+20180-100\)
\(=3+5+20180-100\)
\(=20088\)
/ -3 - 5/ + 20180 - 100
= / -8/ + 20180 - 100
= 8 + 20180 - 100
= 20188 - 100
= 20088.

\(2018^0\left\{15^2:\left[175+2^3.5^2\right]\right\}\\ =1\left\{225:\left[175+8.25\right]\right\}\\ =225:\left[175+200\right]\\ =225:375\\ =\dfrac{3}{5}\)


Ta có : T = 1 + 7 + 72 + ....... + 798 + 799
=> T = (1 + 72) + (7 + 73) + ...... + (796 + 798) + (797 + 799)
=> T = 1.(1 + 49) + 7.(1 + 49) + ...... + 796(1 + 49) + 797.(1 + 49)
=> T = 50 + 7.50 + ...... + 79650 + 797.50
=> T = 50.(1 + 7 + ..... + 796 + 797) chia hết cho 50
`2018^{0}+5^{0}:5^{7}-3`x`7`
`=1+1:78125-21`
`=1/78125-20`
`=-1562499/78125`