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1/3 x 46 +2/3x37 3,2x (95x10) +(8x4)x 187 -(32x 10) x 8,2
=(1/3+2/3) x (46+37) 32x95+32x 187- 32x 82
= 1x 100 32x( 95+187-82)
= 100 = 32 x200
= 6400
120+[55-(11-3.2)2]+12021
= 120+(55-25)+1
= 120+30-1
= 149
-329+(115-101)-(15-440)
= -329+14+425
= 100
Câu 2:
\(a,\Rightarrow x=-23+15=-8\\ b,\Rightarrow5\left(x+4\right)=85\\ \Rightarrow x+4=17\Rightarrow x=13\\ c,\Rightarrow5^{x+2}=24+1=25=5^2\\ \Rightarrow x+2=2\Rightarrow x=0\\ d,\Rightarrow x+4+x+5⋮9\\ \Rightarrow2x+9⋮9\\ \Rightarrow2x⋮9\Rightarrow x\in\left\{0;9\right\}\left(0< x< 10\right)\)
a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5^{300-289}=5^{11}\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}}{3^{17}}=\frac{1}{3}\)
a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}.2^{24}}{3^{17}.2^{24}}=\frac{1}{3}\)
a) 160 - ( 8 . 52 - 6 . 52 )
= 160 - 52 . (8 - 6 )
= 160 - 52 . 2
= 160 - 25 . 2
= 160 - 50
= 110
b) 4 . 25 - ( 25 )7 : ( 24 )8
= 100 - 235 : 232
= 100 - 23
= 100 - 8
= 92
c) 5871 . [ 928 - 165 . 5 ]
= 5871 . [ 928 - 825 ]
= 5871 . 103
= 604 713
d) 111 + 111 = 222
3.23 + 18 : 23 . 22= 3 . 8 + 18 : 8 . 4 = 21 +2,25.4=21+9=30
407+ [(180- 160) : 4 + 32 ]=407+ [(180- 160) : 4 + 9 ]=407+14=421
58 . 75 + 58 . 50 - 58 . 25=58 . (75 + 50 - 25)=58.100=5800
khỏi chép đề nha
a) = 32,768 + 18 : 8 . 4
= 32,768 + 2,25 . 4
= 32,768 + 9
= 41,768
b) = 407 + ( 20 : 4 + 9 )
= 407 + ( 5 + 9 )
= 407 + 14
= 421
c) = 58 . ( 75 + 50 - 25 )
= 58 . 100
= 5800
tk nha
số số hạng của S là :(2015-13):2+1=1002 (số số hạng)
tổng của S là :(2015 +13) .1002 :2 =1015026
2)160 - (4. 5^2 -3 .2^3)
=160-(4.25-3 . 8)
=160-(100-24)
=160-76
=84
3)
a)2015-[117-(23-6)]
=2015-[117-17]
=2015-100
=1915
Bài 1 :
\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)
\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)
\(\Rightarrow M< N\)
Bài 3 :
a) \(t^2+5t-8\) khi \(t=2\)
\(=5^2+2.5-8\)
\(=25+10-8\)
\(=27\)
b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)
\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)
\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)
c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)
\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)
\(\left(1\right)=1^3=1\)
160 - (6.52 - 3.23) + 2021 = 160 - (6.25 - 3.8) + 2021 = 160 - (150 - 24) + 2021 = 160 - 126 + 2021 = 34 + 2021 = 2055