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\(\Rightarrow\left(\dfrac{33}{11}\right)^{2x}=81\Rightarrow3^{2x}=3^4\Rightarrow x=2\)
Đặt \(A=\left(1+\dfrac{7}{9}\right)\left(1+\dfrac{7}{20}\right)\left(1+\dfrac{7}{33}\right)....\left(1+\dfrac{7}{2900}\right)\)
\(B=\left(81-\dfrac{3}{4}\right)\left(81-\dfrac{3^2}{5}\right)\left(81-\dfrac{3^3}{6}\right)....\left(81-\dfrac{3^{2014}}{2017}\right)\)
Ta có:
\(A=\left(1+\dfrac{7}{9}\right)\left(1+\dfrac{7}{20}\right)\left(1+\dfrac{7}{33}\right).....\left(1+\dfrac{7}{2900}\right)\)
\(A=\dfrac{16}{9}.\dfrac{27}{20}.\dfrac{40}{33}.....\dfrac{2907}{2900}\)
\(A=\dfrac{2.8}{1.9}.\dfrac{3.9}{2.10}.\dfrac{4.10}{3.11}.....\dfrac{51.57}{50.58}\)
\(A=\dfrac{2.3.4.5.6....56.57}{1.2.3.4.5.....57.58}=\dfrac{1}{58}\)
\(B=\left(81-\dfrac{3}{4}\right)\left(81-\dfrac{3^2}{5}\right).....\left(81-\dfrac{3^{2014}}{2017}\right)\)
Vì trong dãy số trên có một thừa số là \(\left(81-\dfrac{3^6}{9}\right)=\left(81-81\right)=0\)
\(\Rightarrow B=0\)
Vì \(a=A+B\Rightarrow a=\dfrac{1}{58}+0=\dfrac{1}{58}\)(1)
Thay (1) vào đa thức \(f\left(x\right)=5x-29a\) ta được:
\(f\left(x\right)=5x-29.\dfrac{1}{58}=5x-\dfrac{1}{2}\)
Ta lại có:
\(f\left(x\right)=0\Leftrightarrow5x-\dfrac{1}{2}=0\Leftrightarrow x=\dfrac{1}{10}\)
Vậy nghiệm của đa thức trên là \(\dfrac{1}{10}\)
Chúc bạn học tốt!!!
a.\(\frac{3}{5}\).x-( -\(\frac{1}{2}\))2=\(\sqrt{\frac{9}{16}}\)
<=> \(\frac{3.x}{5}\)-\(\frac{1}{4}\)=\(\frac{3}{4}\)
<=> \(\frac{3.x}{5}\)=1
<=> 3x=5
<=> x= \(\frac{5}{3}\)
b, x-\(\frac{1}{2}\)+\(\frac{1}{3}\)=\(2\frac{1}{3}\)
<=> x=\(2\frac{1}{3}\)+\(\frac{1}{2}\)-\(\frac{1}{3}\)
<=> x=2\(\frac{1}{2}\)
c,33x: 11x =81
<=> ( 3.11)x: 11x=81
<=> 3x. 11x; 11x=81
<=> 3x=81
<=> 3x= 34
<=> x= 4
a, \(\frac{3}{5}x-\frac{1}{4}=\frac{3}{4}\)
\(\frac{3}{5}x=\frac{3}{4}+\frac{1}{4}\)
\(\frac{3}{5}x=1\)
\(x=1:\frac{3}{5}\)
\(x=\frac{5}{3}\)
b, \(x-\frac{1}{2}+\frac{1}{3}=\frac{7}{3}\)
\(x=\frac{7}{3}-\frac{1}{3}+\frac{1}{2}\)
\(x=\frac{5}{2}\)
c, ( 33:11 )x = 81
3x = 81
3x = 34
=> x = 4
Nhớ tích đúng cho mh nha !!!!!!!!!!!
33x :11x =81
↔\(\frac{33^x}{11^x}\)=81
↔(\(\frac{33}{11}\))x=81
↔3x=81
→x=4
\(33^x:11^x=81\)
\(=>\left(33:11\right)^x=81\)
\(3^x=81\)
\(3^x=3^4\)
\(=>x=4\)
Vậy x = 4
a)\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\)
\(\Leftrightarrow\frac{3^5}{5^5}\times x=\frac{3^7}{7^7}\)
\(\Leftrightarrow x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)
\(\Leftrightarrow x=\frac{3^7\times5^5}{7^7\times3^5}\)
\(\Leftrightarrow x=\frac{3^2\times5^5}{7^7}\)
b)\(\left(\frac{-1}{3}\right)^3\times x=\frac{1}{81}\)
\(\Leftrightarrow\frac{\left(-1\right)^3}{3^3}\times x=\frac{1}{3^4}\)
\(\Leftrightarrow x=\frac{1}{3^4}:\frac{-1}{3^3}\)
\(\Leftrightarrow x=\frac{1\times3^3}{3^4\times\left(-1\right)}\)
\(\Leftrightarrow x=\frac{1}{-3}\)
c)\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Leftrightarrow x=\frac{5}{6}\)
d)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
-1/33 . x = 1/81
-1/27 . x = 1/81
x = 1/81 : (-1/27)
x = 1/81 . (-27)
x = -1/3
Vậy x = -1/3