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a) x2 + 5x - 6
= x2 - x + 6x - 6
= x(x - 1) + 6(x - 1)
= (x - 1)(x + 6)
c) x2 + 4x + 3
= x2 - 3x - x + 3
= (x2 - 3x) - (x - 3)
= x(x - 3) - (x - 3)
= (x - 3) - (x - 1)
- a] =-[6x^2 - 7x +2] = - [ 6x^2 - 3x - 4x + 2 ] = -[ 3x [ 2x-1] - 2 [2x - 1]] = - [ 2x - 1] [3x - 2 ]
a,\(xy+3x-7y-21\)
\(=x\left(y+3\right)-7\left(y+3\right)\)
\(=\left(y+3\right)\left(x-7\right)\)
\(b,2xy-15-6x+5y\)
\(=\left(2xy-6x\right)+\left(-15+5y\right)\)
\(=2x\left(y-3\right)-5\left(3-y\right)\)
\(=2x\left(y-3\right)+5\left(y-3\right)\)
\(=\left(y-3\right)\left(2x+5\right)\)
a)x2+5x-6
=x2+6x-x-6
=x(x+6)-(x+6)
=(x-1)(x+6)
b)7x-6x2-2
=-6x2+3x+4x-2
=-3x(2x-1)+2(2x-1)
=(2x-1)(-3x+2)
c)x2+4x+3
=x2+3x+x+3
=x(x+3)+(x+3)
=(x+1)(x+3)
d)2x2+3x-5
=2x2+5x-2x-5
=x(2x+5)-(2x+5)
=(x-1)(2x+5)
1/ \(2x^2+3x-5=\left(2x^2+2x\right)-\left(5x+5\right)=2x\left(x+1\right)-5\left(x+1\right)=\left(x+1\right)\left(2x-5\right)\)
2/ \(16x-5x^2-3=\left(15x-5x^2\right)+\left(x-3\right)=5x\left(3-x\right)-\left(3-x\right)=\left(3-x\right)\left(5x-1\right)\)
3/ \(7x-6x^2-2=\left(3x-6x^2\right)-\left(2-4x\right)=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)
4/ \(x^2+5x-6=\left(x^2-x\right)+\left(6x-6\right)=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)
a,x2 - 13x + 36
= x2 - 4x - 9x + 36
= x(x - 4) - 9(x - 4)
= (x - 4)(x - 9)
b,x2 + 3x - 18
= x2 - 9 + 3x - 9
= (x - 3)(x + 3) + 3(x - 3)
= (x - 3)(x + 3 + 3)
= (x - 3)(x + 6)
c,x2 - 5x - 24
= x2 + 3x - 8x - 24
= x(x + 3) - 8(x + 3)
= (x + 3)(x - 8)
d,3x2 - 16x + 5
= 3x2 - 15x - x + 5
= 3x(x - 5) - (x - 5)
= (x - 5)(3x - 1)
e, 8x2 + 30x + 7
= 8x2 + 2x + 28x + 7
= 2x(4x + 1) + 7(4x + 1)
= (4x + 1)(2x + 7)
g,2x2 - 5x - 12
= 2x2 - 8x + 3x - 12
= 2x(x - 4) + 3(x - 4)
= (x - 4)(2x + 3)
i,x4 + 4
= x4 + 4x2 + 4 - 4x2
= (x2 + 2)2 - (2x)2
= (x2 + 2 - 2x)(x2 + 2 + 2x)
Phân tích đa thức thành nhân tử bằng cách tách một số hạng tử thành nhiều số hạng khác
a) x^2+4x+3
b) 4x^2-4x-3
c)x^2-x-12
d) 4x^4-4x^2-8y^4
Mình viết xuôi theo dạng ax2 + bx + c nhé ;-; cho dễ làm
a) 2x2 + 7x + 3 = 2x2 + x + 6x + 3 = x( 2x + 1 ) + 3( 2x + 1 ) = ( 2x + 1 )( x + 3 )
b) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
c) 3x2 - 7x + 2 = 3x2 - 6x - x + 2 = 3x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 3x - 1 )
d) -6x2 + 7x - 2 = -6x2 + 3x + 4x - 2 = -3x( 2x - 1 ) + 2( 2x - 1 ) = ( 2x - 1 )( 2 - 3x )
e) -3x2 + 7x - 2 = -3x2 + 6x + x - 2 = -3x( x - 2 ) + ( x - 2 ) = ( x - 2 )( 1 - 3x )
f) 2x2 - 5x + 2 = 2x2 - 4x - x + 2 = 2x( x - 2 ) - ( x - 2 ) = ( x - 2 )( 2x - 1 )
g) 3x2 - 8x + 4 = 3x2 - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )
h) 6x2 - 11x + 3 = 6x2 - 2x - 9x + 3 = 2x( 3x - 1 ) - 3( 3x - 1 ) = ( 3x - 1 )( 2x - 3 )
i) 2x2 + 3x - 27 = 2x2 - 6x + 9x - 27 = 2x( x - 3 ) + 9( x - 3 ) = ( x - 3 )( 2x + 9 )
j) 4x2 - 5x + 1 = 4x2 - 4x - x + 1 = 4x( x - 1 ) - ( x - 1 ) = ( x - 1 )( 4x - 1 )
a)x2+4x+3
=x2+x+3x+3
=x(x+1)+3(x+1)
=(x+1)(x+3)
b)2x2+3x-5
=2x2-2x+5x-5
=2x(x-1)+5(x-1)
=(x-1)(2x+5)
c)16x-5x2-3
=-5x2+16x-3
=-5x2+15x+x-3
=-5x(x-3)+(x-3)
=(x-3)(-5x+1)
d)x2+5x-6
=x2-x+6x-6
=x(x-1)+6(x-1)
=(x-1)(x+6)
e)7x-6x2-2
=-6x2+7x-2
=-6x2+4x+3x-2
=-2x(3x-2)+(3x-2)
=(3x-2)(-2x+1)
a, theo đề ra ta có:
= x2 + x + 3x + 3
= ( x2 + x ) + ( 3x + 3 )
= x ( x + 1 ) + 3 ( x + 1 )
= ( x + 3 ). ( x + 1 )