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\(16x-5x^2-3\)
\(=-5x^2+16x-3\)
\(=-5x^2+15x+x-3\)
\(=\left(-5x^2+15x\right)+\left(x-3\right)\)
\(=-5x.\left(x-3\right)+\left(x-3\right)\)
\(=\left(-5x+1\right).\left(x-3\right)\)
\(2x^2+7x+5\)
\(=2x^2+2x+5x+5\)
\(=\left(2x^2+2x\right)+\left(5x+5\right)\)
\(=2x.\left(x+1\right)+5.\left(x+1\right)\)
\(=\left(2x+5\right).\left(x+1\right)\)
\(2x^2+3x+5\) (Bạn xem lại đề nhé.)
\(x^3-3x^2+1-3x\)
\(=\left(x^3+1\right)-\left(3x^2+3x\right)\)
\(=\left(x+1\right).\left(x^2-x+1\right)-3x.\left(x+1\right)\)
\(=\left(x+1\right).\left(x^2-x+1-3x\right)\)
\(=\left(x+1\right).\left(x^2-4x+1\right)\)
\(x^2-4x-5\)
\(=x^2-5x+x-5\)
\(=\left(x^2-5x\right)+\left(x-5\right)\)
\(=x.\left(x-5\right)+\left(x-5\right)\)
\(=\left(x+1\right).\left(x-5\right)\)
\(\left(a^2+1\right)^2-4a^2\)
\(=\left(a^2+1\right)^2-\left(2a\right)^2\)
\(=\left(a^2-2a+1\right).\left(a^2+2a+1\right)\)
\(=\left(a-1\right)^2.\left(a+1\right)^2\)
a)x2+4x+3
=x2+x+3x+3
=x(x+1)+3(x+1)
=(x+1)(x+3)
b)2x2+3x-5
=2x2-2x+5x-5
=2x(x-1)+5(x-1)
=(x-1)(2x+5)
c)16x-5x2-3
=-5x2+16x-3
=-5x2+15x+x-3
=-5x(x-3)+(x-3)
=(x-3)(-5x+1)
d)x2+5x-6
=x2-x+6x-6
=x(x-1)+6(x-1)
=(x-1)(x+6)
e)7x-6x2-2
=-6x2+7x-2
=-6x2+4x+3x-2
=-2x(3x-2)+(3x-2)
=(3x-2)(-2x+1)
a, theo đề ra ta có:
= x2 + x + 3x + 3
= ( x2 + x ) + ( 3x + 3 )
= x ( x + 1 ) + 3 ( x + 1 )
= ( x + 3 ). ( x + 1 )
a) co sai de ko
b)x3-2x2+4x2-8x+3x-6=x2(x-2)+4x(x-2)+3(x-2)=(x-2)(x2+4x+3)=(x-2)(x+3)(x+1)
c)x3-2x2+2x2-4x-3x+6=x2(x-2)+2x(x-2)-3(x-2)=(x-2)(x2+2x-3)=(x-2)(x+3)(x-1)
d)x3-3x2+x2-3x-2x+6=x2(x-3)+x(x-3)-2(x-3)=(x-3)(x2+x-2)=(x-3)(x+2)(x-1)
- a] =-[6x^2 - 7x +2] = - [ 6x^2 - 3x - 4x + 2 ] = -[ 3x [ 2x-1] - 2 [2x - 1]] = - [ 2x - 1] [3x - 2 ]
a)x2+5x-6
=x2+6x-x-6
=x(x+6)-(x+6)
=(x-1)(x+6)
b)7x-6x2-2
=-6x2+3x+4x-2
=-3x(2x-1)+2(2x-1)
=(2x-1)(-3x+2)
c)x2+4x+3
=x2+3x+x+3
=x(x+3)+(x+3)
=(x+1)(x+3)
d)2x2+3x-5
=2x2+5x-2x-5
=x(2x+5)-(2x+5)
=(x-1)(2x+5)
a,\(xy+3x-7y-21\)
\(=x\left(y+3\right)-7\left(y+3\right)\)
\(=\left(y+3\right)\left(x-7\right)\)
\(b,2xy-15-6x+5y\)
\(=\left(2xy-6x\right)+\left(-15+5y\right)\)
\(=2x\left(y-3\right)-5\left(3-y\right)\)
\(=2x\left(y-3\right)+5\left(y-3\right)\)
\(=\left(y-3\right)\left(2x+5\right)\)
a) x2 + 5x - 6
= x2 - x + 6x - 6
= x(x - 1) + 6(x - 1)
= (x - 1)(x + 6)
c) x2 + 4x + 3
= x2 - 3x - x + 3
= (x2 - 3x) - (x - 3)
= x(x - 3) - (x - 3)
= (x - 3) - (x - 1)