Tìm x biết, 3x + 10 =19
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1) |2x-1|=-19-x<=> \(\left[\begin{array}{nghiempt}2x-1=-19-x\\2x-1=19+x\end{array}\right.\)=> x=-6 hoặc x=20
2) |4-3x|=2x-10<=>\(\left[\begin{array}{nghiempt}4-3x=2x-10\\4-3x=10-2x\end{array}\right.\)=> x= 14/6 hoặc x=-6
3) |x|=3+2x<=> \(\left[\begin{array}{nghiempt}x=-3-2x\\x=3+2x\end{array}\right.\)=> x=-1 hoặc x=-3
1) - Nếu 2x - 1 < 0 thì -2x + 1 = -19 - x => -x = -20 => x = 20
- Nếu 2x - 1 > 0 thì 2x - 1 = -19 - x => 3x = -18 => x = -6
2) - Nếu 4 - 3x < 0 thì -4 + 3x = 2x - 10 => 6 = -x => x = -6
- Nếu 4 - 3x > 0 thì 4 - 3x = 2x - 10 => 14 = 5x => x = \(\frac{14}{5}\)
3) - Nếu x < 0 thì -x = 3 + 2x => -3x = 3 => x = -1
- Nếu x > 0 thì x = 3 + 2x => -x = 3 => x = -3
1.
\(\left|2x-1\right|=-19-x\)
\(2x-1=\pm\left(-19-x\right)\)
TH1:
\(2x-1=-19-x\)
\(2x+x=-19-1\)
\(3x=-20\)
\(x=-\frac{20}{3}\)
TH2:
\(2x-1=19+x\)
\(2x-x=19-1\)
\(x=18\)
Vậy x = -20/3 hoặc x = 18
2.
\(\left|4-3x\right|=2x-10\)
\(4-3x=\pm\left(2x-10\right)\)
TH1:
\(4-3x=2x-10\)
\(-3x-2x=-10-4\)
\(-5x=-14\)
\(x=\frac{14}{5}\)
TH2:
\(4-3x=-2x+10\)
\(-3x+2x=10-4\)
\(x=-6\)
Vậy x = 14/5 hoặc x = -6
3.
\(\left|x\right|=3+2x\)
\(x=\pm\left(3+2x\right)\)
TH1:
\(x=3+2x\)
\(x-2x=3\)
\(x=-3\)
TH2:
\(x=-3-2x\)
\(x+2x=-3\)
\(3x=-3\)
\(x=-1\)
1) \(\left|2x-1\right|=-19-x\)
\(=>\orbr{\begin{cases}-19-x=2x-1\\-19-x=-\left(2x-1\right)\end{cases}=>\orbr{\begin{cases}-19+1=2x+x\\-19-x=-2x+1\end{cases}}}\)
\(=>\orbr{\begin{cases}-18=3x\\-x+2x=1+19\end{cases}=>\orbr{\begin{cases}x=-6\\x=20\end{cases}}}\)
2) \(\left|4-3x\right|=2x-10\)
\(=>\orbr{\begin{cases}2x-10=4-3x\\2x-10=-\left(4-3x\right)\end{cases}=>\orbr{\begin{cases}2x+3x=4+10\\2x-10=-4+3x\end{cases}}}\)
\(=>\orbr{\begin{cases}5x=14\\-10+4=3x-2x\end{cases}=>\orbr{\begin{cases}x=\frac{14}{5}\\x=-6\end{cases}}}\)
3) \(\left|x\right|=3+2x\)
\(=>\orbr{\begin{cases}3+2x=x\\3+2x=-x\end{cases}=>\orbr{\begin{cases}2x-x=-3\\2x+x=-3\end{cases}}}\)
\(=>\orbr{\begin{cases}x=-3\\3x=-3\end{cases}=>\orbr{\begin{cases}x=-3\\x=-1\end{cases}}}\)
Ủng hộ mk nha ^_-
a ) 10 x X - 1 - 3 - 5 - 7 - ... - 19 = 2 + 4 + 6 + ... + 20
10 x X - 1 - 3 - 5 - 7 - ... - 19 = 110
10 x X - ( 1 + 3 + 5 + 7 + ... + 19 ) = 110
10 x X - 100 = 110
10 x X = 110 + 100
10 x X = 210
X = 210 : 10
X = 21
264+12x=1800
12x=1536
x=128
(x+73):19=321
x+73=6099
x=6026
2x+3x+4x=18
9x=18
x=2
10<2x<20
=>5<x<10
x=6,7,8,9
\(264+12x=1800\)
\(\Leftrightarrow12x=1536\)
\(\Leftrightarrow x=128\)
==============
\(\left(x+73\right):19=321\)
\(\Leftrightarrow x+73=6099\)
\(\Leftrightarrow x=6026\)
===============
\(2x+3x+4x=18\)
\(\Leftrightarrow x.\left(2+3+4\right)=18\)
\(\Leftrightarrow x.9=18\)
\(\Leftrightarrow x=2\)
================
\(10< 2x< 20\)
..................................
\(2x=12\Leftrightarrow x=6\)
\(2x=14\Leftrightarrow x=7\)
\(2x=16\Leftrightarrow x=8\)
\(2x=18\Leftrightarrow x=9\)
\(x\in\left\{6;7;8;9\right\}\)