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\(a,\left(x+2\right)^{10}+\left(x+2\right)^8=0\\ \Leftrightarrow\left(x+2\right)^8\left[\left(x+2\right)^2+1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+2\right)^8=0\\\left(x+2\right)^2+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+2=0\\\left(x+2\right)^2=-1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\end{matrix}\right.\\ b,\left(x+3\right)^{10}-\left(x+3\right)^8=0\\ \Leftrightarrow\left(x+3\right)^8\left[\left(x+3\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+3\right)^8=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+3=0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x+3=1\\x+3=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\\x=-4\end{matrix}\right.\)
a) x - 8 = 0 : 16 = 0
<=> x = 0+8=8
b) f - 8 = 15:0 = 0
f = 0+8 = 8
c) x = 8 thì ? =0
\(x^3=x\Leftrightarrow x^3-x=0\)
\(\Leftrightarrow x\left(x^2-1\right)=0\Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)
a)(x - 2).(x^2 +1)=0
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x^2+1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x^2=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\\text{vô lí}\end{cases}}}\)
vậy x=2
b)(x^3+8).(2x^2-8)=0
\(\Rightarrow\orbr{\begin{cases}x^3+8=0\\2x^2-8=0\end{cases}\Rightarrow\orbr{\begin{cases}x^3=-8\\2x^2=8\end{cases}\Rightarrow}\orbr{\begin{cases}x=-2\\x^2=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-2\\x=\pm2\end{cases}}}\)
vậy \(x\in\left\{\pm2\right\}\)
a, x : 17 = 0
x = 0 x 17
x = 0
b, 7x - 8 = 713
7x = 713 + 8
7x = 721
x = 721 : 7
x = 103
c, 8 (x - 3) = 0
x - 3 = 0 : 8
x - 3 = 0
x = 0 + 3
x = 3
d, 0 chia bết cứ số nào đều bằng 0 (ngoại trừ 0)
Vậy x \(\in\)N*
a) x : 17 = 0 c) 8 ( x - 3 ) = 0 d) 0 : x = 0
x = 0 x 17 x - 3 = 0 : 8 x = 0 : 0
x = 0 x - 3 = 0 x = 0
b ) 7x - 8 = 0 x = 0 + 3
7x = 0 + 8 x = 3
7x = 8
x = 8 : 7
x = 1,142...
\(\left(x-8\right).\left(x^3+8\right)=0\)
\(\Rightarrow x-8=0\left(x^3+8\ne0\right)\)
\(x=0+8\)
\(\Rightarrow x=8\)
Chúc bạn học tốt!
\(\left(x-8\right)\left(x^3+8\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-8=0\\x^3+8=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x=-2\end{cases}}}\)
Vậy ....
\(\left(x-8\right)\left(x^3+8\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-8=0\\x^3+8=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x^3=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=8\\x=-2\end{cases}}}\)