12-5x-1-3*5x-2=285
273x/94x=81
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MH
6 tháng 10 2021
\(\left(\dfrac{3}{2}\right)^{x+2}=\dfrac{81}{16}\)
\(\left(\dfrac{3}{2}\right)^x.\left(\dfrac{3}{2}\right)^2=\dfrac{81}{16}\)
\(\left(\dfrac{3}{2}\right)^x=\dfrac{81}{16}:\dfrac{9}{4}=\dfrac{9}{4}\)
\(\left(\dfrac{3}{2}\right)^x=\left(\dfrac{3}{2}\right)^2\)
⇔\(x=2\)
6 tháng 10 2021
a: Ta có: \(\left(\dfrac{3}{2}\right)^{x+2}=\dfrac{81}{16}\)
\(\Leftrightarrow x+2=4\)
hay x=2
b: Ta có: \(2^{x^2-5x}=1\)
\(\Leftrightarrow x\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
DH
4 tháng 7 2017
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)
\(\Rightarrow-80x=-480\Rightarrow x=6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)
\(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow15x-8x-5x-6x=36+1-25-12\)
\(\Rightarrow-4x=0\Rightarrow x=0\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow10x-12x-12x=-16+11+16-15\)
\(\Rightarrow-14x=-4\Rightarrow x=\dfrac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)
\(\Rightarrow5x-12x+24x-90x+36=182\)
\(\Rightarrow-73x=182-36\)
\(\Rightarrow-73x=146\Rightarrow x=-2\)
Chúc bạn học tốt!!!
NN
1
HM
2
9 tháng 4 2020
\(\frac{x+3}{12}+\frac{2x+46}{16}=\frac{3x+9}{36}+\frac{5x+81}{6}\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{\frac{3}{2}\left(2x+46\right)}{\frac{3}{2}.16}=\frac{\frac{2}{3}\left(3x+9\right)}{\frac{2}{3}.36}+\frac{4\left(5x+81\right)}{4.6}\)
\(\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{3x+69}{24}=\frac{2x+6}{24}+\frac{20x+324}{24}\)\(\Leftrightarrow2x+6+3x+69=2x+6+20x+324\Leftrightarrow17x=-255\Leftrightarrow x=-\frac{255}{17}\)Vậy \(x=-\frac{255}{17}\)