Tìm x,biết:
(x + 5).(x.2 – 4) = 0 3x – 10 = 2x + 13
3.(4 – x) – 2.(x- 1) = x + 2 2.(x-1) + 3(x-2) = x -4
4.(2x + 7) – 3. (3x – 2) = 24 6x + 23 = 2x –...
Đọc tiếp
Tìm x,biết:
(x + 5).(x.2 – 4) = 0 3x – 10 = 2x + 13
3.(4 – x) – 2.(x- 1) = x + 2 2.(x-1) + 3(x-2) = x -4
4.(2x + 7) – 3. (3x – 2) = 24 6x + 23 = 2x – 12
\(1/\left(x+5\right)\left(x^2-4\right)=0\\ TH1:x+5=0\\ =>x=-5\\ TH2:x^2-4=0\\ =>x^2=4\\ =>x^2=\left(\pm2\right)^2\\ =>x=\pm2\\ 2/3x-10=2x+13\\ =>3x-2x=13+10\\ =>x=23\\ 3/3\left(4-x\right)-2\left(x-1\right)=x+2\\ =>12-3x-2x+2=x+2\\ =>14-5x=x+2\\ =>x+5x=14-2\\ =>6x=12\\ =>x=\dfrac{12}{6}=2\\ 4/2\left(x-1\right)+3\left(x-2\right)=x-4\\ =>2x-2+3x-6=x-4\\ =>5x-8=x-4\\ =>5x-x=-4+8\\ =>4x=4\\ =>x=\dfrac{4}{4}=1\\ 5/4\left(2x+7\right)-3\left(3x-2\right)=24\\ =>8x+28-9x+6=24\\ =>34-x=24\\ =>x=34-24=10\\ 6/6x+23=2x-12\\ =>6x-2x=-12-23\\ =>4x=-35\\ =>x=\dfrac{-35}{4}\)