Tính:
a) 6252 :257
b) 256 :1253
c) 11 . 322 . 37 - 915 / (2 . 314)2
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\(a,A=\left(2^{17}+17^2\right)\left(9^{15}-3^{30}\right).\left(2^4-32^2\right)\)
\(\Rightarrow A=\left(2^{17}+17^2\right)\left(3^{30}-3^{30}\right).\left(2^4-32^2\right)\)
\(\Rightarrow A=\left(2^{17}+17^2\right).0.\left(2^4-32^2\right)\)
\(\Rightarrow A=0.\)
\(\Rightarrow B=\left(2^8.8^3\right):\left(2^5.2^3\right)\)
\(\Rightarrow B=\left(2^8.2^9\right):\left(2^5.2^3\right)\)
\(\Rightarrow B=2^{17}:2^8\)
\(\Rightarrow B=2^9\)
\(\Rightarrow B=512\)
\(c,C=64^4.16^5:4^{20}\)
\(\Rightarrow C=2^{24}.2^{20}:2^{40}\)
\(\Rightarrow C=2^4\)
\(\Rightarrow C=16\)
a: \(A=\left(2^{17}+17^2\right)\cdot\left(2^4-32^2\right)\cdot\left(3^{30}-3^{30}\right)=0\)
b: \(B=\dfrac{2^8\cdot2^9}{2^5\cdot2^3}=2^9\)
c: \(C=2^{24}\cdot2^{20}:2^{40}=2^4=16\)
Bài 2:
a) 37 x 7 - 17 x 11 + 13 x 37 + 17 x 21
b) 55 x 52 : 54 - 28 : 24
c) 311 x 12 + 312 x 5 - 314
`#040911`
`a)`
\(37 \times 7 - 17 \times 11 + 13 \times 37 + 17 \times 21\)
`= 37 \times (7 + 13) + 17 \times (21 - 11)`
`= 37 \times 20 + 17 \times 10`
`= 10 \times (37 \times 2 + 17)`
`= 10 \times 91`
`= 910`
`b)`
\(5^5 \times 5^2 \div 5^4 - 2^8 \div 2^4\)
`=`\(5^{5+2-4}-2^{8-4}\)
`= 5^3 - 2^4`
`= 125 - 16`
`= 109`
`c)`
\(3^{11}\times12+3^{12}\times5-3^{14}\)
`=`\(3^{11}\times\left(12+3\times5-3^3\right)\)
`=`\(3^{11}\times\left(12+15-27\right)\)
`=`\(3^{11}\times0=0\)
a) = 259 - 187 + 481 + 357
= 910
b) = 57 : 54 - 24
= 53 - 24
= 125 - 16
= 109
\(478.615-314.678+385.478-314.322\)
\(=478.\left(615+385\right)-314.\left(678+322\right)\)
\(=478.1000-314.1000\)
\(=478000-314000\)
\(=164000\)
\(478.615-314.678+385.478-314.322\)
\(=478.615+\left(-314\right).678+385.478+\left(-314\right).322\)
\(=478.\left(615+385\right)+\left(-314\right).\left(678+322\right)\)
\(=478.1000+\left(-314\right).1000\)
\(=478000+\left(-314000\right)\)
\(=164000\)
a) 1032-[314-(314+32)]
= 1032-[314-346]
= 1032- (-32)
= 1064
b) 12-11+15-27+11
= 1+15-27+11
= 16 - 27 + 11
= (-11) + 11
= 0
a) 6252 : 257 = (252)2 : 257
= 254 : 257
= 25-3
b) 256 : 1253 = (52)6 : (53)3
= 512 : 59
= 53
c) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-9^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\frac{11.3^{29}-9^{15}}{4.3^{28}}\)
\(=6\)