B=(2+1/3150).3/6517-1/1050.(3+6516/6517)+4/1050-6/3150.6517
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Đặt 3154=a; 6517=b
Theo đề, ta có:
\(B=2\dfrac{1}{a}\cdot\dfrac{3}{b}-\dfrac{3}{a}\cdot\dfrac{b-1}{b}+\dfrac{6}{\dfrac{1}{2}a}-\dfrac{6}{a\cdot b}\)
\(=\dfrac{2a+1}{a}\cdot\dfrac{3}{b}-\dfrac{3b-3}{ab}+\dfrac{12}{a}-\dfrac{6}{a\cdot b}\)
\(=\dfrac{6a+3-3b+3-6}{ab}+\dfrac{12b}{ab}\)
\(=\dfrac{6a-3b+12b}{ab}=\dfrac{6a+9b}{ab}=\dfrac{3\left(2a+3b\right)}{ab}\)
\(=\dfrac{3\left(2\cdot3154+3\cdot6517\right)}{3154\cdot6517}\)
a) x - 4300 - 1250 = 4250 b) x - 6 : 2 - (48 - 8 - 3) = 0
x - 4300 = 4250 + 1250 x - 6 : 2 - 37 = 0
x - 4300 = 5500 x - 3 - 37 = 0
x = 5500 - 4300 x - 3 = 37
x = 1200 x = 37 - 3
x = 34
Ta thấy: \(\left|x+1\right|\ge0\)
\(\Rightarrow\left|x+1\right|^3\ge0\)
\(\Rightarrow\left|x+1\right|^3+1050\ge1050\)
\(\Rightarrow A\ge1050\)
Dấu "=" xảy ra khi \(\left|x+1\right|=0\Leftrightarrow x+1=0\Leftrightarrow x=-1\)
Vậy \(Min_A=1050\) khi \(x=-1\)
\(B=\left(2+\dfrac{1}{3150}\right)\cdot\dfrac{3}{6517}-\dfrac{1}{1050}\cdot\left(3+\dfrac{6516}{6517}\right)+\dfrac{4}{1050}-\dfrac{6}{3150\cdot6517}\\ =\dfrac{6}{6517}+\dfrac{3}{3150\cdot6517}-\dfrac{3}{1050}-\dfrac{6516}{1050\cdot6517}+\dfrac{4}{1050}-\dfrac{6}{3150\cdot6517}\\ =\dfrac{6}{6517}+\left(\dfrac{3}{3150\cdot6517}-\dfrac{6}{3150\cdot6517}\right)+\left(\dfrac{4}{1050}-\dfrac{3}{1050}\right)-\dfrac{6516}{1050\cdot6517}\\ =\dfrac{6}{6517}-\dfrac{3}{3150\cdot6517}+\dfrac{1}{1050}-\dfrac{6516}{1050\cdot6517}\\ =\dfrac{6}{6517}-\dfrac{3}{3150\cdot6517}+\left(\dfrac{6517}{1050\cdot6517}-\dfrac{6516}{1050\cdot6517}\right)\\ =\dfrac{6}{6517}-\dfrac{3}{3150\cdot6517}+\dfrac{1}{1050\cdot6517}\\ =\dfrac{6}{6517}-\dfrac{1}{1050\cdot6517}+\dfrac{1}{1050\cdot6517}\\ =\dfrac{6}{6517}\)
xem lại bài anh ơi