(14*4-4):(13-24:6)*2021+2020
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B/A
\(=\dfrac{1+\dfrac{2020}{2}+1+\dfrac{2019}{3}+...+1+\dfrac{1}{2021}+1}{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2021}+\dfrac{1}{2022}}\)
\(=\dfrac{2022\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2021}+\dfrac{1}{2022}\right)}{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2021}+\dfrac{1}{2022}}=2022\)
a) A=6 -13 +(-14+15+16-17)+(-18+19+20-21)+...+(-2018+2019+2020-2021)+(-2022+2023+2024-2025) +2025
A=-7 +0 +0 +...+0+0 +2025= 2018
B) 7-9+(-10+11+12-13)+(-14+15+16-17)+...+(-2018+2019+2020-2021)+2021
B= -2+0+0+...+0+2021=2019
#Có gì không hiểu thì hỏi nha#
a) A=6 -13 +(-14+15+16-17)+(-18+19+20-21)+...+(-2018+2019+2020-2021)+(-2022+2023+2024-2025) +2025
A=-7 +0 +0 +...+0+0 +2025= 2018
B) 7-9+(-10+11+12-13)+(-14+15+16-17)+...+(-2018+2019+2020-2021)+2021
B= -2+0+0+...+0+2021=2019
#Có gì không hiểu thì hỏi nha#
a: 7/8<8/9<9/10<10/11<11/12
b: 4/5<5/6<6/7<7/8
c: 1/3<3/5<7/9<9/11<11/13
a) Ta có:
2A=2.(12+122+123+...+122020+122021)2�=2.12+122+123+...+122 020+122 021
2A=1+12+122+123+...+122019+1220202�=1+12+122+123+...+122 019+122 020
Suy ra: 2A−A=(1+12+122+123+...+122019+122020)2�−�=1+12+122+123+...+122 019+122 020
−(12+122+123+...+122020+122021)−12+122+123+...+122 020+122 021
Do đó A=1−122021<1�=1−122021<1.
Lại có B=13+14+15+1360=20+15+12+1360=6060=1�=13+14+15+1360=20+15+12+1360=6060=1.
Vậy A < B.
\(=\dfrac{7}{6}\cdot\dfrac{3}{14}-\dfrac{4}{7}\cdot\dfrac{21}{8}+1=\dfrac{1}{4}-\dfrac{3}{2}+1=\dfrac{1}{4}-\dfrac{6}{4}+\dfrac{4}{4}=-\dfrac{1}{4}\)
1-2+3-4+5-6+...+2019-2020+2021
= (1-2) + (3-4) + (4-5) + ... + (2019-2020) + 2021
= -1 + (-1) + (-1) + ... + (-1) + 2021
= -1 . 110 + 2021
= -110 + 2021
=1911
HỌC TỐT !
Lời giải:
$(14\times 4-4):(13-24:6)\times 2021+2020$
$=4\times (14-1):(13-4)\times 2021+2020$
$=4\times 13:9\times 2021+2020=11676,9+2020=13696,9$