cho A=3^2-3^5+3^8-3^11-3^11+...-3^101vaf B =3^104.Tính B+28A
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A = 32 - 35 + 38 - 311 + ...... + 398 - 3101
=> 3A = 35 - 38 + 311 - 314 + ...... + 3101 - 3104
=> 3A + A = (35 - 38 + 311 - 314 + ...... + 3101 - 3104) + (32 - 35 + 38 - 311 + ...... + 398 - 3101)
=> 4A = -3104 + 32
=> 28A = 7(32 - 3104)
=> B + 28A = 3104 + 7(32 - 3104)
=> B + 28A = 7.32 - 6.3104 = 32 (7 - 2.3103)
(DẤU "." LÀ NHÂN NHA BẠN☺)
\(A=3^2-3^5+3^8-3^{11}+...-3^{101}\)
\(\Rightarrow3A=3^5-3^8+3^{11}-3^{14}+...-3^{104}\)
\(\Rightarrow3A+A=\left(3^5-3^8+3^{11}-3^{14}+...-3^{104}\right)+\left(3^2-3^5+3^8-3^{11}+...-3^{101}\right)\)
\(\Rightarrow4A=-3^{104}+3^2\)
\(\Rightarrow28A=7\left(3^2-3^{104}\right)\)
\(\Rightarrow B+28A=3^{104}+7\left(3^2-3^{104}\right)\)
\(\Rightarrow B+28A=7.3^2-6.3^{104}=3^2\left(7-2.3^{103}\right)\)
Ta có : A = 1 + 3 + 32 + .....+ 320
=> 3A = 3 + 32 + 33 +.....+ 321
=> 3A - A = 321 - 1
=> 2A = 321 - 1
=> A = \(\frac{3^{21}-1}{2}\)
Nên : B - A = \(\frac{3^{21}}{2}-\frac{3^{21}-1}{2}=\frac{3^{21}-3^{21}+1}{2}=\frac{1}{2}\)
a.
\(\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{12}\right)+\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{5}{4}+\frac{3}{5}+\frac{3}{8}-\frac{7}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{12}{11}\right)\)
\(=\frac{-9}{10}\)
b.
\(\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{15}\right)+\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{3}{8}-\frac{7}{5}+\frac{5}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{15}{11}\right)\)
\(=\frac{-9}{8}\)
a: \(=\dfrac{7\cdot5+3\cdot9}{45}\cdot\dfrac{2}{3}=\dfrac{62}{45}\cdot\dfrac{2}{3}=\dfrac{124}{135}\)
b: \(=\dfrac{6}{11}\cdot\dfrac{5}{7}=\dfrac{30}{77}\)
c: \(=\dfrac{7}{8}\cdot\dfrac{8-3}{9}=\dfrac{7}{8}\cdot\dfrac{5}{9}=\dfrac{35}{72}\)
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\(\text{#TNam}\)
`a, (7/9+3/5) \times 2/3`
`C1:`
`=62/45 \times 2/3`
`= 124/135`
`C2:`
`= 7/9 \times 2/3 + 3/5 \times 2/3`
`= 14/27 +2/5`
`= 124/135`
`b, `
`C1:`
`= 6/11 \times 5/7`
`=`30/77`
`C2:
`= 9/11 \times 5/7-3/11 \times 5/7`
`= 45/77 -15/77`
`= 30/77`
`c,`
`C1:`
`= 7/8 \times 5/9`
`=35/72`
`C2:`
`= 7/8 \times 8/9- 7/8 \times 1/3`
`= 7/9-7/24`
`=35/72`
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