Câu 6: Tìm x: 4/8 : x = 3/7 |
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1. a
\(\dfrac{8}{5}-\dfrac{5}{6}\cdot\dfrac{3}{4}\)
\(=\dfrac{8}{5}-\dfrac{5\cdot3}{3\cdot2\cdot4}\)
\(=\dfrac{8}{5}-\dfrac{5}{8}=\dfrac{39}{40}\)
1.b
\(=\dfrac{7}{8}+\dfrac{5}{6}\cdot\dfrac{3}{2}\)
\(=\dfrac{7}{8}+\dfrac{5\cdot3}{3\cdot2\cdot2}\)
\(=\dfrac{7}{8}+\dfrac{5}{4}=\dfrac{17}{8}\)
2.a
\(\dfrac{4}{5}+x=\dfrac{11}{10}\)
\(x=\dfrac{11}{10}-\dfrac{4}{5}=\dfrac{3}{10}\)
2.b
\(x-\dfrac{3}{4}=\dfrac{5}{7}\)
\(x=\dfrac{5}{7}+\dfrac{3}{4}=\dfrac{41}{28}\)
a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
3/4 : 6/x : 8/7 = 3/8 : 4/5 : 6/7
3/4 :8/7 :6/x = 15/32 :6/7
21/32 : 6/x = 35/64
6/x = 21/32 : 35/64
6/x=6/5
=>x=6
ủng hộ nha
\(\dfrac{4}{8}\) : \(x\) = \(\dfrac{3}{7}\)
\(x\) = \(\dfrac{4}{8}\) : \(\dfrac{3}{7}\)
\(x\) = \(\dfrac{7}{6}\)
\(\dfrac{4}{8}:x=\dfrac{3}{7}\)
=>\(\dfrac{1}{2}:x=\dfrac{3}{7}\)
=>\(x=\dfrac{1}{2}:\dfrac{3}{7}=\dfrac{1}{2}\times\dfrac{7}{3}=\dfrac{7}{6}\)