Question

[Nguyễn Duy Nguyên]

tính bằng cách thuận tiện

a,11/39+1/3+15/39

b, 8/17+7/17+6/17 giúp tui vs ạ

Answer 1

[Nguyễn Thị Thương Hoài]

a; \(\dfrac{11}{39}\) + \(\dfrac{1}{3}\) + \(\dfrac{15}{39}\)

= (\(\dfrac{11}{39}\) + \(\dfrac{15}{39}\)) + \(\dfrac{1}{3}\)

=  \(\dfrac{26}{39}\) + \(\dfrac{1}{3}\)

= \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)

= 1

Answer 2

[Nguyễn Thị Thương Hoài]

b; \(\dfrac{8}{17}\) + \(\dfrac{7}{17}\) + \(\dfrac{6}{17}\)

= \(\dfrac{8+7+6}{17}\)

= \(\dfrac{21}{17}\)