(2/7 . x + 3/7) : hỗn số 2 và 1/5 - 3/7 = 1
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a: \(\Leftrightarrow\left(\dfrac{13}{4}:x\right)\cdot\left(-\dfrac{5}{4}\right)=\dfrac{-10}{6}-\dfrac{5}{6}=\dfrac{-15}{6}=\dfrac{-5}{2}\)
\(\Leftrightarrow\dfrac{13}{4}:x=\dfrac{5}{2}\cdot\dfrac{5}{4}=\dfrac{25}{8}\)
hay \(x=\dfrac{13}{4}:\dfrac{25}{8}=\dfrac{13}{4}\cdot\dfrac{8}{25}=\dfrac{26}{25}\)
b: \(\Leftrightarrow\dfrac{3}{4}:x=\dfrac{11}{36}-\dfrac{1}{4}=\dfrac{2}{36}=\dfrac{1}{18}\)
=>\(x=\dfrac{3}{4}:\dfrac{1}{18}=\dfrac{54}{4}=\dfrac{27}{2}\)
c: \(\Leftrightarrow\left(-\dfrac{6}{5}+x\right):\left(-3.6\right)=-\dfrac{7}{4}+\dfrac{1}{4}\cdot8=\dfrac{1}{4}\)
=>x-6/5=-9/10
=>x=3/10
Câu 1: \(\frac{5}{7}\):x+\(\frac{2}{3}\)=1\(\frac{1}{3}\)
\(\frac{5}{7}\):x+\(\frac{2}{3}\)=\(\frac{4}{3}\)
\(\frac{5}{7}\):x=\(\frac{4}{3}\) - \(\frac{2}{3}\)
\(\frac{5}{7}\):x=\(\frac{2}{3}\)
x=\(\frac{5}{7}\):\(\frac{2}{3}\)
x=\(\frac{15}{14}\)
Câu 2:x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=2\(\frac{1}{3}\)
x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=\(\frac{7}{3}\)
x*\(\frac{3}{7}\)=\(\frac{7}{3}\)+\(\frac{5}{14}\)
x*\(\frac{3}{7}\)=\(\frac{113}{42}\)
x=\(\frac{113}{42}\):\(\frac{3}{7}\)
x=\(\frac{791}{126}\)
Câu 3: 3\(\frac{5}{7}\)-x*\(\frac{1}{3}\)=1\(\frac{13}{11}\)
\(\frac{26}{7}\)-x*\(\frac{1}{3}\)=\(\frac{24}{11}\)
x*\(\frac{1}{3}\)=\(\frac{26}{7}\)-\(\frac{24}{11}\)
x*\(\frac{1}{3}\)=\(\frac{118}{77}\)
x=\(\frac{118}{77}\):\(\frac{1}{3}\)
x=\(\frac{356}{77}\)
Bài 1: tính: a) 8 và 5/9 : 5 và 1/2 b) 7 và 3/4 - 2 và 1/8 c) 1 và 3/4 x 2 và 5/6 d) 7 - 2 và 2/3 e) 2 và 3/7 x 1 và 3/4 g) 5 và 1/3 : 3 và 1/5 Bài 2: tìm X: X : 3 và 1/3= 2 và 2/5 + 7/10 Và là biểu thị cho hỗn số nhé
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a)\(\left(x+3\right)\times5+1=20\Leftrightarrow5x+15=19\)
\(\Leftrightarrow5x=4\Leftrightarrow x=\frac{4}{5}\)
b)sai đề
c)\(2\frac{3}{7}\times x+1\frac{5}{4}=5\frac{3}{42}\)\(\Leftrightarrow\frac{17}{7}\times x+\frac{9}{4}=\frac{71}{14}\) \(\Leftrightarrow\frac{17}{7}\times x+\frac{63}{28}=\frac{142}{28}\)
\(\Leftrightarrow\frac{17}{7}\times x=\frac{79}{28}\Leftrightarrow x=\frac{17}{7}:\frac{79}{28}\) \(\Leftrightarrow x=\frac{17}{7}\times\frac{28}{79}\Leftrightarrow x=\frac{476}{553}=\frac{68}{79}\)
d)\(10\frac{2}{3}-x:\frac{6}{7}=8\frac{1}{3}-6\frac{2}{7}\Leftrightarrow\frac{32}{3}-x:\frac{6}{7}=\frac{25}{3}-\frac{44}{7}\) \(\Leftrightarrow\frac{224}{21}-x:\frac{6}{7}=\frac{75}{21}-\frac{132}{21}\Leftrightarrow-\frac{57}{21}-\frac{224}{21}\)
\(\Leftrightarrow-x:\frac{6}{7}=-\frac{281}{21}\Leftrightarrow-x=-\frac{281}{21}\times\frac{6}{7}\) \(\Leftrightarrow-x=-\frac{1686}{147}\Leftrightarrow x=\frac{562}{49}=11\frac{23}{49}\)
x+\(\dfrac{3}{15}=\dfrac{1}{3}\)
<=>\(x=\dfrac{1}{3}-\dfrac{3}{15}\)
<=>x=\(\dfrac{5}{15}-\dfrac{3}{15}\)
<=>x=\(\dfrac{2}{15}\)
Vậy S={\(\dfrac{2}{15}\)}
\(-5\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}x-\dfrac{5}{6}\)
<=>\(-5x-1-\dfrac{1}{2}x+\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\)
<=>\(-\dfrac{11}{2}x-\dfrac{3}{2}x=-\dfrac{5}{6}+1-\dfrac{1}{3}\)
<=>-7x=\(-\dfrac{1}{6}\)
<=>x=\(\dfrac{7}{6}\)
Vậy S={\(\dfrac{7}{6}\)}
\(x\cdot6\dfrac{2}{7}+\dfrac{3}{7}\cdot2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\dfrac{11}{5}-\dfrac{3}{7}=-2\)
<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\left(\dfrac{11}{5}-1\right)=-2\)
<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\dfrac{6}{5}=-2\)
<=>\(\dfrac{44}{7}x\)\(+\dfrac{18}{35}=-2\)
<=>\(\dfrac{44}{7}x=-2-\dfrac{18}{35}\)
<=>\(\dfrac{44}{7}x=-\dfrac{88}{35}\)
<=>x=\(-\dfrac{88}{35}\cdot\dfrac{7}{44}\)
<=>x=\(-\dfrac{2}{5}\)
Vậy S={\(-\dfrac{2}{5}\)}
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
\(\Leftrightarrow x\cdot\dfrac{12}{7}=\dfrac{15}{6}=\dfrac{5}{2}\)
hay \(x=\dfrac{5}{2}:\dfrac{12}{7}=\dfrac{5}{2}\cdot\dfrac{7}{12}=\dfrac{35}{24}\)
Bài 1:
a) \(2\)\(\dfrac{2}{3}\)\(=\dfrac{8}{3}\)
b) \(1\)\(\dfrac{5}{7}=\dfrac{12}{7}\)
Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để được hỗ trợ tốt hơn.
(\(\dfrac{2}{7}\)\(x\) + \(\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = 1
(\(\dfrac{2}{7}x+\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) = 1 + \(\dfrac{3}{7}\)
(\(\dfrac{2}{7}x+\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) = \(\dfrac{10}{7}\)
\(\dfrac{2x+3}{7}\) : \(\dfrac{11}{5}\) = \(\dfrac{10}{7}\)
\(\dfrac{2x+3}{7}\) = \(\dfrac{10}{7}\)
\(\dfrac{2x+3}{7}\) = \(\dfrac{10}{7}\times\dfrac{11}{5}\)
\(\dfrac{2x+3}{7}\) = \(\dfrac{22}{7}\)
2\(x\) + 3 = \(\dfrac{22}{7}\) x 7
2\(x\) + 3 = 22
2\(x\) = 22 - 3
2\(x\) = 19
\(x\) = \(\dfrac{19}{2}\)
Vậy \(x=\dfrac{19}{2}\)