1+1+1+1+1+1+1+1+1+1+1+1+1+1+1-14-1+1=?
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(=\dfrac{15}{14}\times\dfrac{15}{14}\times\dfrac{16}{15}\times\dfrac{17}{16}\times\dfrac{18}{17}=\dfrac{15}{14}\times\dfrac{18}{14}=\dfrac{135}{98}\)
\(\left(1+\dfrac{1}{14}\right)\left(1+\dfrac{1}{14}\right)\times\left(1+\dfrac{1}{15}\right)\times\left(1+\dfrac{1}{16}\right)\times\left(1+\dfrac{1}{17}\right)\)
\(=\dfrac{15}{14}.\dfrac{15}{14}.\dfrac{16}{15}.\dfrac{17}{16}.\dfrac{18}{17}\)
\(=\dfrac{15}{14}.\dfrac{18}{14}\)
\(\dfrac{135}{98}\)
(1/10+-1/10)+(1/11+-1/11)+(1/12+-1/12)+(-1/13+1/13)+(-1/14+1/14)+(-1/15+1/15)+1/16
=0 + 0 +0 + 0 +0 +0 +1/16
=1/16
Ta có: A\(=\dfrac{1}{9}.\dfrac{1}{10}+\dfrac{1}{10}.\dfrac{1}{11}+\dfrac{1}{11}.\dfrac{1}{12}+\dfrac{1}{12}.\dfrac{1}{13}+\dfrac{1}{13}.\dfrac{1}{14}+\dfrac{1}{14}.\dfrac{1}{15}\)
\(=\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{15}\)
\(=\dfrac{1}{9}-\dfrac{1}{15}=\dfrac{2}{45}\)
\(A=\dfrac{1}{9}.\dfrac{1}{10}+\dfrac{1}{10}.\dfrac{1}{11}+\dfrac{1}{11}.\dfrac{1}{12}+\dfrac{1}{12}.\dfrac{1}{13}+\dfrac{1}{13}.\dfrac{1}{14}+\dfrac{1}{14}.\dfrac{1}{15}\)
\(=\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{15}\)
\(=\dfrac{1}{9}-\dfrac{1}{15}\)
\(=\dfrac{2}{45}\)
-Chúc bạn học tốt-
( 1 + 1/13 ) x ( 1 + 1/14 ) x ( 1 + 1/15 ) x ( 1 + 1/16 ) x ( 1 + 1/17 )
= 14/13 x 15/14 x 16/15 x 17/16 x 18/17
= 18/13
1
\(=1\)