Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(1-\dfrac{1}{5}\right)\times\left(1-\dfrac{1}{6}\right)\times\left(1-\dfrac{1}{7}\right)\times\left(1-\dfrac{1}{8}\right)\times\left(1-\dfrac{1}{9}\right)\)
\(=\dfrac{4}{5}\times\dfrac{5}{6}\times\dfrac{6}{7}\times\dfrac{7}{8}\times\dfrac{8}{9}\)
\(=\dfrac{4}{9}\)
tính nhanh đúng ko?
= 4/5 x 5/6 x 6/7 x 7/8 x 8/9
= 4 x 5 x 6 x 7 x 8/ 5 x 6 x 7 x 8 x 9
= 4/9
( 1 + 1/13 ) x ( 1 + 1/14 ) x ( 1 + 1/15 ) x ( 1 + 1/16 ) x ( 1 + 1/17 )
= 14/13 x 15/14 x 16/15 x 17/16 x 18/17
= 18/13
\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+...+\dfrac{1}{x}=\dfrac{127}{256}\)
Đặt VT là A
\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\)
\(2A-A=\left(1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{x}\right)=\dfrac{127}{256}\)
\(\Leftrightarrow A=1-\dfrac{1}{x}=\dfrac{127}{256}\)
\(\Leftrightarrow\dfrac{1}{x}=\dfrac{129}{256}\)
\(\Rightarrow x=\dfrac{256}{129}\)
\(\dfrac{9}{10}+\dfrac{3}{5}\times\dfrac{1}{6}=\dfrac{9}{10}+\dfrac{3}{30}=\dfrac{27}{30}+\dfrac{3}{30}=1\)
\(\dfrac{31}{12}-\dfrac{7}{5}:\dfrac{14}{15}=\dfrac{31}{12}-\dfrac{7}{5}\times\dfrac{15}{14}=\dfrac{31}{12}-\dfrac{3}{2}=\dfrac{31}{12}-\dfrac{18}{12}=\dfrac{13}{12}\)
\(\dfrac{4}{7}\times\dfrac{2}{5}:\dfrac{10}{9}=\dfrac{14}{35}\times\dfrac{9}{10}=\dfrac{9}{25}\)
\(\frac{1}{4}< 1\) ; \(\frac{3}{7}< 1\) ; \(\frac{9}{5}>1\)
\(\frac{7}{3}>1\) ; \(\frac{14}{15}< 1\) ; \(\frac{16}{16}=1\) ; \(\frac{14}{11}>1\)
1/4 < 1; 3/7 < 1; 9/5 > 1; 14/15 < 1; 16/16 = 1; 14/11 > 1.
\(\dfrac{1}{4444}< 1,\dfrac{3}{7}< 1,\dfrac{9}{5}>1,\dfrac{7}{3}>1,\dfrac{14}{15}< 1,\dfrac{16}{16}=1,\dfrac{14}{11}>1\)
\(=\dfrac{15}{14}\times\dfrac{15}{14}\times\dfrac{16}{15}\times\dfrac{17}{16}\times\dfrac{18}{17}=\dfrac{15}{14}\times\dfrac{18}{14}=\dfrac{135}{98}\)
\(\left(1+\dfrac{1}{14}\right)\left(1+\dfrac{1}{14}\right)\times\left(1+\dfrac{1}{15}\right)\times\left(1+\dfrac{1}{16}\right)\times\left(1+\dfrac{1}{17}\right)\)
\(=\dfrac{15}{14}.\dfrac{15}{14}.\dfrac{16}{15}.\dfrac{17}{16}.\dfrac{18}{17}\)
\(=\dfrac{15}{14}.\dfrac{18}{14}\)
\(\dfrac{135}{98}\)