21=x+170/x (x khác 0)
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a, 170 - ( 4+5 *x ) = 101
4+ 5*x = 170 - 101
4+5 *x = 69
5*x = 69 - 4
5*x= 65
x= 65: 5
x=13
b, 21 * ( 32 - x ) = 21
32 -x= 21 : 21
32 - x = 1
x = 32 -1
x= 31
Bài làm :
\(a,170-\left(4+5.x\right)=101\)
\(4+5.x=170-101\)
\(4+5.x=69\)
\(5x=65\)
\(x=13\)
\(b,21.\left(32-x\right)=21\)
\(32-x=1\)
\(x=31\)
Học tốt nhé
\(\frac{149-x}{25}+\frac{170-x}{23}+\frac{187-x}{21}+\frac{200-x}{19}=10\)
\(\Rightarrow\frac{149-x}{25}-1+\frac{170-x}{23}-2+\frac{187-x}{21}-3+\frac{200-x}{19}-4=0\)
\(\Rightarrow\frac{124-x}{25}+\frac{124-x}{23}+\frac{124-x}{21}+\frac{124-x}{19}=0\)
\(\Rightarrow\left(124-x\right)\left(\frac{1}{25}+\frac{1}{23}+\frac{1}{21}+\frac{1}{19}\right)=0\)
Mà \(\frac{1}{25}+\frac{1}{23}+\frac{1}{21}+\frac{1}{19}>0\Rightarrow x-124=0\Rightarrow x=124\)
a) Suy ra : \(x\in BCNN\left(14,21\right)\)
14 = 2.7
21 = 3.7
=> BCNN (14,21)=7.2.3=42
Vậy x = 42
b) 200-(2x+6)=4^3
=>200-2x-6=64
=>194-2x=64
=>2x=194-64=130
=>x=65
a) x ⋮ 14 và x ⋮ 21
Mà x ≠ 0 và x là số nhỏ nhất nên:
\(x\in BCNN\left(14,21\right)\)
Ta có:
\(14=2\cdot7\)
\(21=3\cdot7\)
\(\Rightarrow x=BCNN\left(14,21\right)=7\cdot2\cdot3=42\)
b) \(200-\left(2x+6\right)=4^3\)
\(\Rightarrow2x+6=200-4^3\)
\(\Rightarrow2x+6=200-64\)
\(\Rightarrow2x+6=136\)
\(\Rightarrow2x=136-6\)
\(\Rightarrow2x=130\)
\(\Rightarrow x=130:2\)
\(\Rightarrow x=65\)
=> \(\frac{x-241}{17}-1+\frac{x-220}{19}-2+\frac{x-195}{21}-3+\frac{x-170}{22}-4=0\)
<=> \(\left(\frac{x-241}{17}-\frac{17}{17}\right)+\left(\frac{x-220}{19}-\frac{38}{19}\right)+\left(\frac{x-195}{21}-\frac{63}{21}\right)+\left(\frac{x-170}{22}-\frac{88}{22}\right)=0\)
<=> \(\frac{x-258}{17}+\frac{x-258}{19}+\frac{x-258}{21}+\frac{x-258}{22}=0\)
<=> \(\left(x-258\right).\left(\frac{1}{17}+\frac{1}{19}+\frac{1}{21}+\frac{1}{22}\right)=0\)
<=> x - 258 = 0 do \(\left(\frac{1}{17}+\frac{1}{19}+\frac{1}{21}+\frac{1}{22}\right)\ne0\)
=> x = 258
10=1+2+3+4
X=241+17x1=258
X=220+19x2=258
X=195+21x3=258
X=170+22x4=258.
Bấm vào chữ "Đúng 0" là hiện ra câu trả lời của mik ák
câu 1 là : Tìm x để A khác 0 \(A=\frac{-4x^2}{3-x}\)
Ta có : \(\frac{149-x}{25}+\frac{170-x}{23}+\frac{187-x}{21}+\frac{200-x}{19}=10\)
\(\Leftrightarrow\frac{149-x}{25}-1+\frac{170-x}{23}-2+\frac{187-x}{21}-3+\frac{200-x}{19}-4=0\)
\(\Leftrightarrow\frac{124-x}{25}+\frac{124-x}{23}+\frac{124-x}{21}+\frac{124-x}{19}=0\)
\(\Leftrightarrow\left(124-x\right)\left(\frac{1}{25}+\frac{1}{23}+\frac{1}{21}+\frac{1}{19}\right)=0\)
Vì \(\frac{1}{25}+\frac{1}{23}+\frac{1}{21}+\frac{1}{19}\ne0\)
Nên : 124 - x = 0
<=> x = 124
Vậy x = 124
x+170/x là $\frac{x+170}{x}$ hay $x+\frac{170}{x}$ hả bạn?
\(21\) = \(\dfrac{x+170}{x}\) (\(x\) \(\ne\) 0)
21 \(\times\) \(x\) = \(x\) + 170
21 \(\times\) \(x\) - \(x\) = 170
\(x\) \(\times\) (21 - 1) = 170
\(x\) \(\times\) 20 = 170
\(x\) = 170 : 20
\(x\) = \(\dfrac{17}{2}\)