(3x-24)x73=2x74
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45,65 x73 + 11 x91,3 + 45,65 x5
= 3332,45 + 1004,3 + 228,25
=4336,75 + 228,25
= 4565
10000-47x72-47x28
=10000-47x72-47x47-28
=47x(10000-72-28)
=47x0
=0
MIK CHỈ GIẢI DƯỢC PHẦM ĐẦU THUI
SORRY NHÉ
- 1000 - 47 x 72 - 47 x 28
= 47 x (1000 - 72 - 28 )
= 47 x 0
= 0
\(3x-24+3x^2=0\\ \Leftrightarrow x^2+x-8=0 \)
\(\Delta=1^2-4.\left(-8\right)=1+32=33\)
\(\Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{-1-\sqrt{33}}{2}\\x_2=\dfrac{-1+\sqrt{33}}{2}\end{matrix}\right.\)
\(\Leftrightarrow x^2+x-8=0\)
\(\Leftrightarrow x^2+x+\dfrac{1}{4}-\dfrac{33}{4}=0\)
\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{33}{4}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{\sqrt{33}}{2}\\x+\dfrac{1}{2}=-\dfrac{\sqrt{33}}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\sqrt{33}-1}{2}\\x=\dfrac{-\sqrt{33}-1}{2}\end{matrix}\right.\)
\(3^{x+2}-3^x=72\)
\(\Rightarrow3^x\cdot\left(3^2-1\right)=72\)
\(\Rightarrow3^x\cdot\left(9-1\right)=72\)
\(\Rightarrow3^x\cdot8=72\)
\(\Rightarrow3^x=\dfrac{72}{8}\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
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Xem lại đề
\(5x-\left(24-2x\right)=\left(-24\right)+20+3x\)
\(5x+\left(-24\right)+2x=\left(-24\right)+20+3x\)
\(7x+\left(-24\right)=\left(-24\right)+20+3x\)
\(7x=20+3x\)
\(\left(7-3\right)x=20\)
\(4x=20\)
\(x=20:4\)
\(x=5\)
5x- (24 - 2x) = -24 + 20 + 3x
5x- 24 + 2x = -4 + 3x
5x + 2x - 3x = 24 - 4
4x = 20
x = 20 \(\div\)4
x = 5
Vậy x = 5
3x+2 - 3x =24
..............
➙ x =1
vậy x=1
3x+2- 3x= 24
(=)3x*32-3x=24
(=)3x*32-3x*1=24
3x*(32-1)=24
3x*(9-1)=24
3x*8=24
3x=24/8=3
=)x=1
=)
\(\left(3x-2^4\right).7^3=2.7^4\)
\(=>3x-2^4=2.7^4:7^3\)
\(=>3x-2^4=2.7=14\)
\(=>3x=14+2^4\)
\(=>3x=30\)
\(=>x=30:3\)
\(=>x=10\)
Vậy..
x = 10