1-1/8-1/6 ạ
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a: Ta có: \(\dfrac{x+6}{8}+\dfrac{x+8}{6}+\dfrac{x+1}{13}+3=0\)
\(\Leftrightarrow\dfrac{x+14}{6}+\dfrac{x+14}{6}+\dfrac{x+14}{13}=0\)
\(\Leftrightarrow x+14=0\)
hay x=-14
b) Ta có: \(\dfrac{x-5}{10}+\dfrac{x-7}{8}+\dfrac{x-1}{14}=3\)
\(\Leftrightarrow\dfrac{x-15}{10}+\dfrac{x-15}{8}+\dfrac{x-15}{14}=0\)
\(\Leftrightarrow x-15=0\)
hay x=15
a.\(\left(\frac{1}{3}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{7}\right)+\left(\frac{1}{7}-\frac{1}{8}\right)=\)
\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}=\frac{1}{3}-\frac{1}{8}=\frac{5}{24}\)
b. \(\frac{10}{17}-\frac{5}{13}-\frac{7}{17}-\frac{8}{13}=\left(\frac{10}{17}-\frac{7}{17}\right)-\left(\frac{5}{13}+\frac{8}{13}\right)=1-1=0\)
a, \(\frac{3}{10}+\frac{5}{8}=\frac{24}{80}+\frac{50}{80}=\frac{74}{80}=\frac{37}{40}\)
b, \(\frac{1}{8}+\frac{5}{6}=\frac{3}{24}+\frac{20}{24}=\frac{23}{24}\)
c, \(\frac{1}{3}+\frac{1}{6}+\frac{1}{8}=\frac{8}{24}+\frac{4}{24}+\frac{3}{24}=\frac{15}{24}=\frac{5}{8}\)
#Fox
\(C=-1-1-1-...-1\)
C có \(\left(2016-1+1\right):2=1008\left(\text{số hạng -1}\right)\)
\(\Rightarrow C=\left(-1\right)\cdot1008=-1008\)
\(D=\left(1+2+...+15\right)-\left(6+7+...+20\right)\\ D=\dfrac{\left(15+1\right)\left(15+1-1\right)}{2}-\dfrac{\left(20+6\right)\left(20-6+1\right)}{2}\\ D=\dfrac{16\cdot15-26\cdot15}{2}=-75\)
a)\(\left(5x+2\right)\left(2x-6\right)=0\\ \left\{{}\begin{matrix}5x+2=0\Leftrightarrow5x=-2\Leftrightarrow x=\dfrac{-2}{5}\\2x-6=0\Leftrightarrow2x=6\Leftrightarrow x=\dfrac{6}{2}=3\end{matrix}\right.\)
b)\(\dfrac{5x}{2x+2}+1=\dfrac{8}{x+1}\\ \Leftrightarrow\dfrac{5x}{2\left(x+1\right)}+1=\dfrac{8}{x+1}\\ \Leftrightarrow\dfrac{5x+2\left(x+1\right)}{2\left(x+1\right)}=\dfrac{2\cdot8}{2\left(x+1\right)}\\ \Leftrightarrow5x+2\left(x+1\right)=16\\ \Leftrightarrow5x+2x+2=16\\ \Leftrightarrow5x+2x=16-2\\ \Leftrightarrow7x=14\\ \Leftrightarrow x=\dfrac{14}{7}=2\)
a, <=>5x+2=0<=>x=-2/5
<=>2x-6=0<=>x=6/2=3
mik có tí việc ko lm hết cho bn đc xl
Ta có:
\(-\left(-\dfrac{1}{6}\right)^{100}=-\left(\dfrac{1}{6}\right)^{100}=-\left[\left(\dfrac{1}{6}\right)^2\right]^{50}=-\left(\dfrac{1}{36}\right)^{50}\)
\(-\left(-\dfrac{1}{8}\right)^{150}=-\left(\dfrac{1}{8}\right)^{150}=-\left[\left(\dfrac{1}{8}\right)^3\right]^{50}=-\left(\dfrac{1}{512}\right)^{50}\)
Mà: \(\dfrac{1}{36}>\dfrac{1}{512}\)
\(\Rightarrow\left(\dfrac{1}{36}\right)^{50}>\left(\dfrac{1}{512}\right)^{50}\)
\(\Rightarrow-\left(\dfrac{1}{36}\right)^{50}< -\left(\dfrac{1}{512}\right)^{50}\)
\(\Rightarrow-\left(\dfrac{-1}{6}\right)^{100}< -\left(\dfrac{-1}{8}\right)^{150}\)
` 1 - 1/8 - 1/6 `
`= 7/8 - 1/6 `
`= 21/24 - 4/24 `
`= 17/24`
ko khó đâu