c) (12x-4³).8³=4.8⁴
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\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)
c) \(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-64=4.8^4:8^3\)
\(12x-64=32\)
\(12x=32+64\)
\(12x=96\)
\(x=\dfrac{96}{12}\)
\(x=8\)
d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)
\(720:\left(41-2x+5\right):5=35\)
\(720:\left(46-2x\right)=35.5\)
\(720:\left(46-2x\right)=175\)
\(46-2x=720:175\)
\(46-2x=\dfrac{144}{35}\)
\(2x=46-\dfrac{144}{35}\)
\(2x=\dfrac{1466}{35}\)
\(x=\dfrac{1466}{35}:2\)
\(x=\dfrac{733}{35}\)
a) 2x-3=-x+6
2x - 3 + x - 6 =0
3x -9 = 0
3x = 9
x = 9 : 3
x= 3
c/ \(\left(-12x-4^3\right).8^3=4.8^4\)
\(\left(-12x-64\right).512=16384\)
\(-12x-64=\dfrac{16384}{512}=32\)
\(-12x=32+64=96\)
\(x=\dfrac{96}{\left(-12\right)}=-8\)
a <=>12x-4^3=32
<=>12x=96
<=>x=8
b, <=>3x-6=27
<=>3x=33
<=>x=11
c, <=>119-(x-6)=102
<=>x-6=17
<=>x=23
hok tot
a) ( 12x - 43 ) . 83 = 4.84
=> ( 12x - 43 ) : 4 = 84 : 83
=> ( 12x - 43 ) : 4 = 8
=> 12x - 43 = 8 . 4
=> 12x - 64 = 32
=> 12x = 96
=> x = 8
b) ( 3x - 6 ) . 3 = 34
=> ( 3x - 6 ) = 34 : 31
=> 3x - 6 = 33
=> 3x - 6 = 27
=> 3x = 33
=> x = 11
c) 2448 : [ 119 - ( x - 6 ) ] = 24
=> 119 - ( x - 6 ) = 102
=> x - 6 = 7
=> x = 13
a) \(\left[\left(4x+28\right).3+55\right]:5=35\)
\(\Leftrightarrow\left(4x+28\right).3+55=35.5\)
\(\Leftrightarrow\left(4x+28\right).3+55=175\)
\(\Leftrightarrow\left(4x+28\right).3=175-55\)
\(\Leftrightarrow\left(4x+28\right).3=120\)
\(\Leftrightarrow4x+28=120:3\)
\(\Leftrightarrow4x+28=40\)
\(\Leftrightarrow4x=40-28\)
\(\Leftrightarrow4x=12\)
\(\Leftrightarrow x=12:4\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
b) \(\left(12x-4^3\right).8^3=4.8^4\)
\(\Leftrightarrow12x-4^3=4.8^4:8^3\)
\(\Leftrightarrow12x-4^3=4.8^{4-3}\)
\(\Leftrightarrow12x-4^3=4.8\)
\(\Leftrightarrow12x-4^3=32\)
\(\Leftrightarrow12x-64=32\)
\(\Leftrightarrow12x=32+64\)
\(\Leftrightarrow12x=96\)
\(\Leftrightarrow x=96:12\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
c) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=8.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x-5\right)=720:40\)
\(\Leftrightarrow41-\left(2x-5\right)=18\)
\(\Leftrightarrow2x-5=41-18\)
\(\Leftrightarrow2x-5=23\)
\(\Leftrightarrow2x=23+5\)
\(\Leftrightarrow2x=28\)
\(\Leftrightarrow x=28:2\)
\(\Leftrightarrow x=14\)
Vậy \(x=14\)
bn ơi nếu muốn ân smux
thì bn ấn vào chữ X2
ạ bn viết thế này
mình ko có hiểu
a,
128-3x-12=23
3x=128-12-23
3x=93
x=93:3
= 31
b,
(12x+84+55):5=35
12x+84+55=35.5
12x+84+55=175
12x=175-55-84
12x=36
x=36:12
x=3
\(4^2x+4^2.10=160\)
\(4^2\left(x+10\right)=160\)
\(16\left(x+10\right)=160\)
\(x+10=10\)
\(x=0\)
vay \(x=0\)
\(\left(12x-4^3\right).8^3=4.8^4\)
\(\left(12x-4^3\right).8^3-4.8^4=0\)
\(\left(12x-64\right).8^3-4.8^4=0\)
\(8^3\left(12x-64-32\right)=0\)
\(12x-96=0\)
\(12x=96\)
\(x=8\)
vay \(x=8\)
`@` `\text {Ans}`
`\downarrow`
`c)`
`(12x - 4^3) * 8^3 = 4*8^4`
`=> 12x - 4^3 = 4*8^4 \div 8^3`
`=> 12x - 4^3 = 4*8`
`=> 12x - 2^6 = 2^2 * 2^3`
`=> 12x - 2^6 = 2^5`
`=> 12x = 2^5 + 2^6`
`=> 12x = 96`
`=> x = 96 \div 12`
`=> x = 8`
Vậy, `x = 8.`
=>(12x-64)=4*8^4/8^3=4*8=32
=>12x=96
=>x=8