tính bằng cách hợp lí :
12 x 3 + 5 x 3 + 2 x 3
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HV
1
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
17 tháng 4 2023
\(\dfrac{3}{8}+\dfrac{9}{2}\times\dfrac{12}{16}-\dfrac{9}{4}:3\)
= \(\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{9}{2}\times\dfrac{3}{4}-\dfrac{3}{4}\times3:3\)
= \(\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{9}{2}\times\dfrac{3}{4}-\dfrac{3}{4}\times1\)
= \(\dfrac{3}{4}\times\left(\dfrac{1}{2}+\dfrac{9}{2}-1\right)\)
= \(\dfrac{3}{4}\times\left(5-1\right)\)
= \(\dfrac{3}{4}\times4\)
= 3
VQ
24 tháng 9 2023
\(a,1\dfrac{4}{7}.3\dfrac{4}{11}.3\dfrac{11}{15}.5\dfrac{5}{8}\)
\(=\dfrac{11}{7}.\dfrac{27}{11}.\dfrac{56}{15}.\dfrac{45}{8}\)
\(=\dfrac{11.27.56.45}{7.11.15.8}\)
\(=\dfrac{1.3.7.3}{1.1.1.1}\)
\(=63\)
\(b,\dfrac{3}{4}.1\dfrac{1}{2}+\dfrac{3}{4}.\dfrac{1}{2}\)
\(=\dfrac{3}{4}.\left(1\dfrac{1}{2}+\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}.2\)
\(=\dfrac{3}{2}\)
Y
26 tháng 6 2023
\(a,\dfrac{3}{2}\times\dfrac{4}{5}\times\dfrac{2}{3}\times\dfrac{15}{4}\\ =\dfrac{3\times4\times2\times15}{2\times5\times3\times4}\\ =\dfrac{3\times4\times2\times5\times3}{2\times5\times3\times4}\\ =3\)
\(b,\dfrac{6}{7}\times\dfrac{5}{8}\times\dfrac{7}{3}\times\dfrac{7}{6}\times\dfrac{8}{5}\\ =\dfrac{6\times5\times7\times7\times8}{7\times8\times3\times6\times5}\\ =\dfrac{7}{3}\)
VN
Võ Ngọc Phương
VIP
26 tháng 6 2023
a) \(\dfrac{3}{2}\times\dfrac{4}{5}\times\dfrac{2}{3}\times\dfrac{15}{4}\)
\(=\left(\dfrac{3}{2}\times\dfrac{2}{3}\right)\times\left(\dfrac{4}{5}\times\dfrac{15}{4}\right)\)
\(=1\times3\)
\(=3\)
b) \(\dfrac{6}{7}\times\dfrac{5}{8}\times\dfrac{7}{3}\times\dfrac{7}{6}\times\dfrac{8}{5}\)
\(=\left(\dfrac{6}{7}\times\dfrac{7}{6}\right)\times\left(\dfrac{5}{8}\times\dfrac{8}{5}\right)\times\dfrac{7}{3}\)
\(=1\times1\times\dfrac{7}{3}\)
\(=\dfrac{7}{3}\)
Chúc bạn học tốt
TD
21 tháng 1 2017
1. Tính bằng cách hợp lí nhất:
a) 2155 - (174 + 2155) + (-68 + 174)
= 2155 - 174 - 2155 + (-68) + 174
= (2155 - 2155) + (-174 + 174) + (-68)
= 0 + 0 + (-68)
= -68
b) -25 . 72 + 25 . 21 - 49 . 25
= 25 . (-72) + 25 . 21 - 49 . 25
= 25 . (-72 + 21 - 49)
= 25 . (-100)
= -2500
2. Tìm số nguyên x, biết:
a) 5 - (10 - x) = 7
=> 5 - 10 + x = 7
=> -5 + x = 7
=> x = 7 - (-5)
=> x = 12
b) -2|3x - 1| = -22
=> |3x - 1| = -22 : (-2)
=> |3x - 1| = 11
=> \(\orbr{\begin{cases}3x-1=11\\3x-1=-11\end{cases}}\)
=> \(\orbr{\begin{cases}3x=11+1\\3x=-11+1\end{cases}}\)
=> \(\orbr{\begin{cases}3x=12\\3x=10\left(bỏ\right)\end{cases}}\)
=> x = 12 : 3
=> x = 4
c) -12(x - 5) + 7(3 - x) = 5
=> -12x - (-12) . 5 + 7 . 3 - 7x = 5
=> -12x - (-60) + 21 - 7x = 5
=> -12x + 60 + 21 - 7x = 5
=> -12x + 81 - 7x = 5
=> -12x - 7x = 5 - 81
=> -19x = -76
=> 19x = 76
=> x = 76 : 19
=> x = 4
15 tháng 5 2017
2d, Ta có (x-3)(x-5)<0
<=> x-3 và x-5 phải trái dấu. Mà ta thấy x-3> x-5 => x-3 là số dương và x-5 là số âm
=>x-3>0 => x>3
x-5 <0 => x<5
=> 3<x<5
=> x = 4
Vậy x=4 thì (x-3)(x-5)<0
6 tháng 8 2023
a: A=(-x)^3+3*(-x)^2*2+3*(-x)*2^2+2^3=(-x+2)^3
=(28+2)^3=30^3=27000
b: \(C=\left(x+2y-2\right)^3=\left(20+2\cdot9-2\right)^3\)
=36^3
c: 11^3-1
=(11-1)(11^2+11+1)
=10*(121+12)
=1330
d: x^3-y^3=(x-y)^3+3xy(x-y)
=6^3+3*6*9
=216+162
=378
H
8 tháng 2 2023
`5`
`a, -7/21 +(1+1/3)`
`=-7/21 + ( 3/3 + 1/3)`
`=-7/21+ 4/3`
`=-7/21+ 28/21`
`= 21/21`
`=1`
`b, 2/15 + ( 5/9 + (-6)/9)`
`= 2/15 + (-1/9)`
`= 1/45`
`c, (9-1/5+3/12) +(-3/4)`
`= ( 45/5-1/5 + 3/12)+(-3/4)`
`= ( 44/5 + 3/12)+(-3/4)`
`= 9,05 +(-0,75)`
`=8,3`
`6`
`x+7/8 =13/12`
`=>x= 13/12 -7/8`
`=>x=5/24`
`-------`
`-(-6)/12 -x=9/48`
`=> 6/12 -x=9/48`
`=>x= 6/12-9/48`
`=>x=5/16`
`---------`
`x+4/6 =5/25 -(-7)/15`
`=>x+4/6 =1/5 + 7/15`
`=> x+ 4/6=10/15`
`=>x=10/15 -4/6`
`=>x=0`
`----------`
`x+4/5 = 6/20 -(-7)/3`
`=>x+4/5 = 6/20 +7/3`
`=>x+4/5 = 79/30`
`=>x=79/30 -4/5`
`=>x= 79/30-24/30`
`=>x= 55/30`
`=>x= 11/6`
VN
8 tháng 2 2023
\(5)\)
\(A=\dfrac{-7}{21}+\left(1+\dfrac{1}{3}\right)\)
\(A=\dfrac{-7}{21}+\dfrac{4}{3}\)
\(A=\dfrac{-7}{21}+\dfrac{28}{21}\)
\(A=1\)
\(--------------\)
\(B=\dfrac{2}{15}+\left(\dfrac{5}{9}+\dfrac{-6}{9}\right)\)
\(B=\dfrac{2}{15}+\dfrac{-1}{9}\)
\(B=\dfrac{18}{135}+\dfrac{-15}{135}\)
\(B=\dfrac{1}{45}\)
\(------------\)
\(C=9-\dfrac{1}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)
\(C=\dfrac{44}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)
\(C=\dfrac{528}{60}+\dfrac{15}{60}+\dfrac{-3}{4}\)
\(C=\dfrac{181}{20}+\dfrac{-3}{4}\)
\(C=\dfrac{181}{20}+\dfrac{-15}{20}\)
\(C=\dfrac{83}{10}\)
\(6)\)
\(a)\) \(x+\dfrac{7}{8}=\dfrac{13}{12}\)
\(x=\dfrac{13}{12}-\dfrac{7}{8}\)
\(x=\dfrac{104}{96}-\dfrac{84}{96}\)
\(x=\dfrac{5}{24}\)
\(b)\) \(\dfrac{-6}{12}-x=\dfrac{9}{48}\)
\(\dfrac{-1}{2}-x=\dfrac{3}{16}\)
\(x=\dfrac{-1}{2}-\dfrac{3}{16}\)
\(x=\dfrac{-8}{16}-\dfrac{3}{16}\)
\(x=\dfrac{-11}{16}\)
\(c)\) \(x+\dfrac{4}{6}=\dfrac{5}{25}-\left(-\dfrac{7}{15}\right)\)
\(x+\dfrac{4}{6}=\dfrac{5}{25}+\dfrac{7}{15}\)
\(x+\dfrac{4}{6}=\dfrac{75}{375}+\dfrac{105}{375}\)
\(x+\dfrac{4}{6}=\dfrac{12}{25}\)
\(x=\dfrac{12}{25}-\dfrac{4}{6}\)
\(x=\dfrac{72}{150}-\dfrac{100}{150}\)
\(x=\dfrac{-14}{75}\)
\(d)\) \(x+\dfrac{4}{5}=\dfrac{6}{20}-\left(-\dfrac{7}{3}\right)\)
\(x+\dfrac{4}{5}=\dfrac{6}{20}+\dfrac{7}{3}\)
\(x+\dfrac{4}{5}=\dfrac{18}{60}+\dfrac{140}{60}\)
\(x+\dfrac{4}{5}=\dfrac{79}{30}\)
\(x=\dfrac{79}{30}-\dfrac{4}{5}\)
\(x=\dfrac{79}{30}-\dfrac{24}{30}\)
\(x=\dfrac{11}{6}\)
Noo Phước Thịnh
12*3+5*3+2*3=(12+5+2)*3.
=19*3.
=57.
12 x 3 + 5 x 3 + 2 x 3
= 3 x ( 12 + 5 + 2 )
= 3 x 19
= 57