Bài 6: Tìm số nguyên x, biếtA, 3 – (17 – x) = 289 – (36 + 289)B, 25 – (x + 5) = -415 – (15 – 415)C, 34 + (21 – x) = (3747 – 30) – 3746D, -2x – (x – 17) = 34 – (-x + 25)E, 17x + (-16x – 37) = 2x + 43G, (x + 12). (x – 3) = 0H, (-x + 5). (3 – x) = 0K, -28 – 7. |-3x + 15| = - 70M, 12 – 2. (-x + 3)2 = - 38N, - {-3x + 2. [45 – x – 3. (3x + 7) – 2x] + 4x} = 55Bài 7: So sánhA, (-99). 98. (-97) với 0B, (-5). (-4). (-3). (-2). (-1) với 0C, (-245)....
Đọc tiếp
Bài 6: Tìm số nguyên x, biết
A, 3 – (17 – x) = 289 – (36 + 289)
B, 25 – (x + 5) = -415 – (15 – 415)
C, 34 + (21 – x) = (3747 – 30) – 3746
D, -2x – (x – 17) = 34 – (-x + 25)
E, 17x + (-16x – 37) = 2x + 43
G, (x + 12). (x – 3) = 0
H, (-x + 5). (3 – x) = 0
K, -28 – 7. |-3x + 15| = - 70
M, 12 – 2. (-x + 3)2 = - 38
N, - {-3x + 2. [45 – x – 3. (3x + 7) – 2x] + 4x} = 55
Bài 7: So sánh
A, (-99). 98. (-97) với 0
B, (-5). (-4). (-3). (-2). (-1) với 0
C, (-245). (-47). (-199) với 123. (+315)
D, 2987. (-1974). (+243). 0 với 0
E, (-12). (-45) : (-27) với |-1|
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
nhanh mik tick cho nha