tìm số tự nhiên n biết
a)11 mũ n = 1331 b) n mũ 3= 125 c) 5 mũ 4 = n d) ( n + 1 mũ 2 ) = 9
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27 tháng 7 2023
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
27 tháng 7 2023
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
13 tháng 9 2020
a) \(2^n:4=16\Rightarrow2^n:2^2=2^4\Rightarrow2^{n-2}=2^4\Rightarrow n-2=4\Rightarrow n=6\)
b) \(6\cdot2^n+3\cdot2^n=9\cdot2^9\)
=> \(\left(6+3\right)\cdot2^n=9\cdot2^9\)
=> \(9\cdot2^n=9\cdot2^9\Rightarrow n=9\)
c) \(3^n:3^2=243\)
=> \(3^{n-2}=3^5\)
=> n - 2 = 5 => n = 7
d) 25 < 5n < 3125
=> 52 < 5n < 55
=> n \(\in\){3;4}
M
9 tháng 9 2017
a, (-1/5)n=-1/125
=> (-1/5)n=(-1/5)3
=> n=3
b, (-2/11)m=4/121
=> (-2/11)m=(2/11)2
=> m=2
VM
13 tháng 8 2019
3.
a) \(\left(x-1\right)^3=125\)
=> \(\left(x-1\right)^3=5^3\)
=> \(x-1=5\)
=> \(x=5+1\)
=> \(x=6\)
Vậy \(x=6.\)
b) \(2^{x+2}-2^x=96\)
=> \(2^x.\left(2^2-1\right)=96\)
=> \(2^x.3=96\)
=> \(2^x=96:3\)
=> \(2^x=32\)
=> \(2^x=2^5\)
=> \(x=5\)
Vậy \(x=5.\)
c) \(\left(2x+1\right)^3=343\)
=> \(\left(2x+1\right)^3=7^3\)
=> \(2x+1=7\)
=> \(2x=7-1\)
=> \(2x=6\)
=> \(x=6:2\)
=> \(x=3\)
Vậy \(x=3.\)
Chúc bạn học tốt!
27 tháng 7 2018
\(a,2^n=16\Leftrightarrow2^n=2^4\Leftrightarrow n=4\)
\(3^n=243\Rightarrow3^n=3^5\Leftrightarrow n=5\)
\(b,4^n=4096\Rightarrow4^n=4^6\Leftrightarrow n=6\)
\(5^n=15625\Rightarrow5^n=5^6\Leftrightarrow n=6\)
\(c,6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Leftrightarrow n=0\)
\(4^{n-1}=1024\Rightarrow4^{n-1}=4^5\Rightarrow n-1=5\Leftrightarrow n=6\)
T
27 tháng 7 2018
\(a.\) \(2^n=16\Rightarrow2^n=2^4\Leftrightarrow n=4\)
\(3^n=243\Rightarrow3^n=3^5\Leftrightarrow n=5\)
\(b.\) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
\(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
\(c.\) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
\(4^{n-1}=1024\Rightarrow4^{n-1}=4^5\Rightarrow n-1=5\Rightarrow n=6\)
NQ
15 tháng 8 2017
a) 5x+x+1=\(\dfrac{125}{25}\)
\(\leftrightarrow\) 52x+1 =51
\(\leftrightarrow\) 2x+1=1
\(\leftrightarrow\)2x=0
\(\leftrightarrow\) x=0
a) \(11^n=1331\)
\(\Rightarrow11^n=11^3\)
\(\Rightarrow n=3\)
b) \(n^3=125\)
\(\Rightarrow n^3=5^3\)
\(\Rightarrow n=5\)
c) \(5^4=n\)
\(\Rightarrow625=n\)
\(\Rightarrow n=625\)
d) \(\left(n+1^2\right)=9\)
\(\Rightarrow n+1=9\)
\(\Rightarrow n=9-1\)
\(\Rightarrow n=8\)
a) 11^n = 1331
⇒ 11^n = 11^3
⇔ n = 3
b) n^ 3 = 125
⇒ n^3 = 5^3
⇔ n = 5
c) 5^4 = n
⇒ n = 625
d) ( n + 1^2 ) = 9
⇒ ( n + 1 ) = 9
⇒ n = 8