15-15/7-15/12 = ?
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\(=\frac{12}{15}.\left(\frac{2}{7}+\frac{3}{7}+\frac{1}{7}+\frac{1}{7}\right)\)
\(=\frac{12}{15}.1\)
\(=\frac{12}{15}=\frac{4}{5}\)
...=-15-9=-24
...=4+7=11
...=-12-13=-25
...=13+10=23
...=-4-7=-11
...=-9+13=4
...=12+0=12
...=0-7=-7
...=0+3=3
...=15-17=-2
...=-6
...=-23
...=15-15=0
\(\frac{15-\frac{15}{7}-\frac{15}{12}}{3-\frac{3}{7}-\frac{3}{12}}\)
\(=\frac{\frac{90}{7}-\frac{15}{12}}{\frac{18}{7}-\frac{3}{12}}\)
\(=\frac{\frac{325}{28}}{\frac{65}{28}}\)
\(=\frac{35}{17}\)
\(\frac{15-\frac{15}{7}-\frac{15}{12}}{3-\frac{3}{7}-\frac{3}{12}}\)
\(=\frac{\frac{90}{7}-\frac{15}{12}}{\frac{18}{7}-\frac{3}{12}}\)
\(=\frac{\frac{325}{28}}{\frac{65}{28}}\)
\(=5\)
\(\frac{15-\frac{15}{7}-\frac{15}{12}}{3-\frac{3}{7}-\frac{3}{12}}\)
= \(\frac{15.\left(1-\frac{1}{7}-\frac{1}{12}\right)}{3.\left(1-\frac{1}{7}-\frac{1}{12}\right)}\)
= \(\frac{15}{3}\)
= 5
\(\frac{15-\frac{15}{7}-\frac{15}{12}-\frac{15}{98}}{18-\frac{18}{7}-\frac{18}{12}-\frac{18}{98}}\)= \(\frac{15-15\left(\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}{18-18\left(\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}\)=\(\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}\)= \(\frac{15}{18}\)=\(\frac{5}{6}\)
\(15-\dfrac{15}{7}-\dfrac{15}{12}=\dfrac{1260}{84}-\dfrac{180}{84}-\dfrac{105}{84}\)
\(=\dfrac{975}{84}=\dfrac{325}{28}\)
`@` `\text {Ans}`
`\downarrow`
`15 - 15/7 - 15/12`
`= 15/1 - 15/7 - 15/12`
`= 90/7 - 15/12`
`= 325/28`