chuyển hỗn số thành phân số rồi tính:
\(7\frac{8}{4}\)\(\times\)\(1\frac{4}{5}\)
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\(4\frac{2}{3}+3\frac{2}{7}=\frac{14}{3}+\frac{23}{7}=\frac{98+69}{21}=\frac{167}{21}\)
\(1\frac{3}{4}\times2\frac{5}{6}=\frac{7}{4}\times\frac{17}{6}=\frac{119}{24}\)
\(7\frac{3}{4}-2\frac{1}{8}=\frac{31}{4}-\frac{17}{8}=\frac{62-17}{8}=\frac{45}{8}\)
\(8\frac{5}{9}:5\frac{1}{2}=\frac{77}{9}:\frac{11}{2}=\frac{77}{9}\times\frac{2}{11}=\frac{154}{99}=\frac{14}{9}\)
1.Chuyển các hỗn số sau thành phân số:
\(2\frac{1}{3}\)= \(\frac{7}{3}\)
\(4\frac{2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{12}{4}\)
\(9\frac{5}{7}=\frac{68}{7}\)
\(10\frac{3}{10}=\frac{103}{10}\)
2.Chuyển các hỗn số thành phân số rồi thực hiện phép tính:
\(\alpha.\)\(2\frac{1}{3}+4\frac{1}{3}=\frac{7}{3}+\frac{13}{3}=\frac{20}{3}\)
b. \(9\frac{2}{7}+5\frac{3}{7}=\frac{65}{7}+\frac{38}{7}=\frac{103}{7}\)
c. \(10\frac{3}{10}+4\frac{7}{10}=\frac{103}{10}+\frac{47}{10}=\frac{150}{10}\)=\(15\)
d. \(2\frac{1}{3}+5\frac{1}{4}=\frac{7}{3}+\frac{21}{4}=\frac{21}{12}+\frac{63}{12}=\frac{84}{12}\)= 7
e. \(3\frac{2}{5}+2\frac{1}{7}=\frac{17}{5}+\frac{15}{7}=\frac{119}{35}+\frac{75}{35}=\frac{194}{35}\)
g. \(8\frac{1}{6}+2\frac{1}{7}=\frac{49}{6}+\frac{15}{7}=\frac{342}{42}+\frac{90}{42}=\frac{432}{42}\)
7/3/8 - 4/5/8 = 59/8 - 37/8 = 12
2/1/4 +5/1/4 = 9/4 + 21/4 = 15/2
3/1/4 x 2/3/5 = 13/4 x 13/5 =11/20
\(7\frac{3}{8}-4\frac{5}{8}=\frac{59}{8}-\frac{37}{8}=\frac{22}{8}\)\(=\)\(2,75\)
\(2\frac{1}{4}+5\frac{1}{4}=\frac{9}{4}+\frac{21}{4}=\frac{30}{4}=7,5\)
\(3\frac{1}{4}\times2\frac{3}{5}=\frac{13}{4}\times\frac{13}{5}=\frac{169}{20}=8,45\)
#Minyun
b) 4 1/8 : (4 - 1/4) = 33 /8 : ( 16/4 - 1/4) = 33/8 : 15/4 = 11/10
c) 1 4/35 + 3 4/7 * 3 1/5 = 39/35 + 25/7 * 16/5 = 39/35 + 80/7 = 39/35 + 400/35 = 439/35
1 4/35 + 3 4/7 * 3 1/5 = 39/35 + 25/7 * 16/5 = 39/35 + 80/7 = 39/35 + 400/35 = 439/35
\(1\dfrac{4}{35}+3\dfrac{4}{7}\times3\dfrac{1}{5}=\dfrac{39}{35}+\dfrac{25}{7}\times\dfrac{16}{5}=\dfrac{39}{35}+\dfrac{80}{7}=\dfrac{39}{35}+\dfrac{400}{35}=\dfrac{39+400}{35}=\dfrac{439}{35}\)
1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
\(4\frac{2}{3}+2\frac{3}{4}.7\frac{3}{11}=\frac{14}{3}+\frac{11}{4}.\frac{80}{11}=\frac{14}{3}+20=\frac{14}{3}+\frac{60}{3}=\frac{74}{3}\)
\(4\frac{2}{3}+2\frac{3}{4}\times7\frac{3}{11}\)
\(=\frac{14}{3}+\frac{11}{4}\times\frac{80}{11}\)
\(=\frac{14}{3}+\frac{11\times80}{4\times11}\)
\(=\frac{14}{3}+20\)
\(=\frac{14}{3}+\frac{60}{3}\)
\(=\frac{74}{3}\)
\(9\)x \(\frac{9}{5}\)= \(\frac{81}{5}\)
tkmk nha
\(7\frac{8}{4}=9\)
\(1\frac{4}{5}=\frac{9}{5}\)
\(9\times\frac{9}{5}=\frac{81}{5}=16\frac{1}{5}\)