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1.Chuyển các hỗn số sau thành phân số:
\(2\frac{1}{3}\)= \(\frac{7}{3}\)
\(4\frac{2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{12}{4}\)
\(9\frac{5}{7}=\frac{68}{7}\)
\(10\frac{3}{10}=\frac{103}{10}\)
2.Chuyển các hỗn số thành phân số rồi thực hiện phép tính:
\(\alpha.\)\(2\frac{1}{3}+4\frac{1}{3}=\frac{7}{3}+\frac{13}{3}=\frac{20}{3}\)
b. \(9\frac{2}{7}+5\frac{3}{7}=\frac{65}{7}+\frac{38}{7}=\frac{103}{7}\)
c. \(10\frac{3}{10}+4\frac{7}{10}=\frac{103}{10}+\frac{47}{10}=\frac{150}{10}\)=\(15\)
d. \(2\frac{1}{3}+5\frac{1}{4}=\frac{7}{3}+\frac{21}{4}=\frac{21}{12}+\frac{63}{12}=\frac{84}{12}\)= 7
e. \(3\frac{2}{5}+2\frac{1}{7}=\frac{17}{5}+\frac{15}{7}=\frac{119}{35}+\frac{75}{35}=\frac{194}{35}\)
g. \(8\frac{1}{6}+2\frac{1}{7}=\frac{49}{6}+\frac{15}{7}=\frac{342}{42}+\frac{90}{42}=\frac{432}{42}\)
1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
\(2\frac{1}{3}=\frac{7}{3};4\frac{2}{5}=\frac{22}{5};3\frac{1}{4}=\frac{13}{4};9\frac{5}{7}=\frac{68}{7};10\frac{3}{10}=\frac{103}{10}\)
9 2/7+5 3/7=65/7+38/7=103/7
10 3/10-4 7/10=103/10-47/10=56/10
\(4\frac{2}{3}+2\frac{3}{4}.7\frac{3}{11}=\frac{14}{3}+\frac{11}{4}.\frac{80}{11}=\frac{14}{3}+20=\frac{14}{3}+\frac{60}{3}=\frac{74}{3}\)
\(4\frac{2}{3}+2\frac{3}{4}\times7\frac{3}{11}\)
\(=\frac{14}{3}+\frac{11}{4}\times\frac{80}{11}\)
\(=\frac{14}{3}+\frac{11\times80}{4\times11}\)
\(=\frac{14}{3}+20\)
\(=\frac{14}{3}+\frac{60}{3}\)
\(=\frac{74}{3}\)
\(3\frac{2}{5}=\frac{3\cdot5+2}{5}=\frac{17}{5}\)
\(2\frac{1}{7}=\frac{2\cdot7+1}{7}=\frac{15}{7}\)
\(8\frac{1}{6}=\frac{8\cdot6+1}{6}=\frac{49}{6}\)
\(2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{5}{2}\)
\(3\frac{2}{5}\cdot2\frac{1}{7}=\frac{17}{5}\cdot\frac{15}{7}=\frac{51}{7}\)
\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{49}{6}\cdot\frac{2}{5}=\frac{49}{15}\)
\(2\frac{3}{5}=\frac{2x5+3}{5}=\frac{10+3}{5}=\frac{13}{5}\)
\(5\frac{4}{9}=\frac{5x9+4}{9}=\frac{45+4}{9}=\frac{49}{9}\)
\(9\frac{3}{8}=\frac{9x8+3}{8}=\frac{72+3}{8}=\frac{75}{8}\)
\(12\frac{7}{10}=\frac{12x10+7}{10}=\frac{120+7}{10}=\frac{127}{10}\)
\(2\frac{3}{5}=\frac{13}{5}\)
\(5\frac{4}{9}=\frac{49}{9}\)
\(9\frac{3}{8}=\frac{75}{8}\)
\(12\frac{7}{10}=\frac{127}{10}\)
65/7+38/7=103/7
103/10-47/10=56/10
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