(-6)2 + 2 va 36+2
Giúp mik vs!!!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Sửa đề: +2023^2-2024^2
C=(1-2)(1+2)+(3-4)(3+4)+...+(2023-2024)(2023+2024)
=-(1+2+3+4+...+2023+2024)
=-2024*2025/2=-2049300
\(2^{x+1}-2^x=3^2\)
\(\Rightarrow2^x\cdot\left(2-1\right)=9\)
\(\Rightarrow2^x=9\)
\(\Rightarrow x\in\varnothing\)
\(2^{x+1}-2^x=3^2\)
=>2^x*2-2^x=9
=>2^x=9
=>\(x\in\varnothing\)
x+1<x+2<x+3<x+4 ( với mọi x)
\(\dfrac{1}{100}\) < \(\dfrac{1}{99}\)<\(\dfrac{1}{3}\) <\(\dfrac{1}{2}\)
=>\(\dfrac{x+1}{100}\)+\(\dfrac{x+2}{99}\) <\(\dfrac{x+3}{3}\)+\(\dfrac{x+4}{2}\) là đúng
b, ( 5/2 - x ) ^2
=25/4-4/5x+x^2
c,( xy/2 - x/3 ) ( xy/2 + x/3)
=(xy/2)^2-(x/3)^2
c: \(\left(\dfrac{xy}{2}-\dfrac{x}{3}\right)\left(\dfrac{xy}{2}+\dfrac{x}{3}\right)=\dfrac{x^2y^2}{4}-\dfrac{x^2}{9}\)
e: \(\left(2x+3y\right)^2=4x^2+12xy+9y^2\)
\(a)245^2+490\cdot54+54^2-199^2\\=(245^2+2\cdot245\cdot54+54^2)-199^2\\=(245+54)^2-199^2\\=299^2-199^2\\=(299-199)(299+199)\\=100\cdot498\\=49800\\---\\b)356^2-356\cdot246+123^2-133^2\\=(356^2-2\cdot356\cdot123+123^2)-133^2\\=(356-123)^2-133^2\\=233^2-133^2\\=(233-133)(233+133)\\=100\cdot366\\=36600\)
\(---\)
\(c)468^2-412^2-110\cdot412-55^2\\=468^2-(412^2+110\cdot412+55^2)\\=468^2-(412^2+2\cdot412\cdot55+55^2)\\=468^2-(412+55)^2\\=468^2-467^2\\=(468-467)(468+467)\\=1\cdot935\\=935\\---\)
\(d)615^2+250\cdot615+125^2-540^2\\=(615^2+2\cdot615\cdot125+125^2)-540^2\\=(615+125)^2-540^2\\=740^2-540^2\\=(740-540)(740+540)\\=200\cdot1280\\=256000\)
#\(Toru\)
\(2x^2y-x^3-xy+1+x^3+2xy^2-2\)
\(=\left(-x^3+x^3\right)+\left(1-2\right)+2x^2y-xy+2xy^2\)
\(=0-1+2x^2y-xy+2xy^2\)
\(=2x^2y-xy+2xy^2-1\)
(-6)2 + 2 = 36 + 2