11/25 x (y + y x 5 - 23/55) + 3/14 x 56/25 = 1
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\(a,\left(23+x\right)-\left(56-x\right)=\left(23+7\right)-\left(56-7\right)=30-49=-19\\ b,25-x-\left(29+y-8\right)=25-13-\left(29+11-8\right)=12-32=-20\)
Lời giải:
a. $(-12)-x=(-12)-(-28)=-12+28=28-12=16$
b. $(23+x)-(56-x)=(23+7)-(56-7)=30-49=-19$
c. $25-x-(29+y-8)=25-13 -(29+11-8)=12-32=-20$
a) Cách 1: Thay x = 7, ta có:
(23 + x) - (56 - x)
= (23 + 7) - (56 - 7)
= 30 - 49
= -19
Cách 2:
Thay x = 7, ta có:
(23 + x) - (56 - x)
= (23 + 7) - (56 - 7)
= 23 + 7 - 56 + 7
= 30 - 56 + 7
= (-26) + 7
=-19.
b) Cách 1: Thay x = 13, y = 11, ta có:
25 - x - (29 + y - 8)
= 25 - 13 - (29 + 11 - 8)
= 12 - 32
= -20.
Cách 2: Thay x = 13, y = 11, ta có:
25 - x - (29 + y - 8)
= 25 - 13 - (29 + 11 - 8)
= 25 - 13 - 29 - 11 + 8
= 12 - 29 - 11 + 8
= (-17) - 11 + 8
= (-28) + 8
=-20.
Câu 1:
a: =>-2x-x+17=34+x-25
=>-3x+17=x+9
=>-4x=-8
hay x=2
b: =>17x+16x+27=2x+43
=>33x+27=2x+43
=>31x=16
hay x=16/31
c: =>-2x-3x+51=34+2x-50
=>-5x+51=2x-16
=>-7x=-67
hay x=67/7
e: 3x-32>-5x+1
=>8x>33
hay x>33/8
a) Ta có: (23+x)−(56−x)(23+x)−(56−x)
=23+x-56+x
=2x-33
=2⋅7−33=14−33=−19=2⋅7−33=14−33=−19
b) Ta có: 25−x−(29+y−8)25−x−(29+y−8)
=25−x−29−y+8=25−x−29−y+8
=4−x−y=4−x−y
=4−13−11=4−24=−20
A.ta có:(23+x)-(56+x)
=2x-33
=2×7-33
=14-33
=-19
B.ta có:25-x-(29+y-8)
=25-x-29-y+8
=4-x-y
=4-13
=4-24
=-20
1. 11(x-9)=77
x-9=7
x=16
2. 4(x-3)=48
x-3=12
x=15
3.3(x-8)=81
(x-8)=27
x=35
x + (-23 ) = -100 + 77
x + ( -23 ) = -23
x = -23 - ( -23 )
x = -23 + 23
x = 0
( -15 ) + x = ( -14 ) - ( -57 )
( -15 ) + x = 43
x = 43 - ( -15 )
x = 43 + 15
x = 58
Mấy câu còn lại cũng dễ bn tự làm nha! Bye bye
\(x+\left(-23\right)=-100+77\)
\(\Leftrightarrow x-23=-23\)
\(\Leftrightarrow x=-23+23\)
\(\Leftrightarrow x=0\)
\(-15+x=-14-\left(-57\right)\)
\(\Leftrightarrow-15+x=43\)
\(\Leftrightarrow x=43+15\)
\(\Leftrightarrow x=48\)
\(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Leftrightarrow11-26=x-16\)
\(\Leftrightarrow x-16=15\)
\(\Leftrightarrow x=-15+16\)
\(\Leftrightarrow x=1\)
\(x-\left(17-x\right)=x-7\)
\(\Leftrightarrow x-17+x=x-7\)
\(\Leftrightarrow2x+17=x-7\)
\(\Leftrightarrow x-2x=7-17\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
\(\left(-12\right)^{2x}=56+10.13x\)
\(\Leftrightarrow144^x=56+10.13x\)
\(\dfrac{7}{2}+\dfrac{2}{25}=\dfrac{7\times25}{2\times25}+\dfrac{2\times2}{25\times2}=\dfrac{175}{50}+\dfrac{4}{50}=\dfrac{179}{50}\)
\(\dfrac{23}{5}-\dfrac{11}{3}=\dfrac{23\times3}{5\times3}-\dfrac{11\times5}{3\times5}=\dfrac{69}{15}-\dfrac{55}{15}=\dfrac{14}{15}\)
\(\dfrac{3}{7}-\dfrac{1}{14}=\dfrac{3\times2}{7\times2}-\dfrac{1}{14}=\dfrac{6}{14}-\dfrac{1}{14}=\dfrac{5}{14}\)
\(\dfrac{8}{5}:\dfrac{1}{3}=\dfrac{8}{5}\times3=\dfrac{8\times3}{5}=\dfrac{24}{5}\)
\(2:\dfrac{5}{3}=2\times\dfrac{3}{5}=\dfrac{2\times3}{5}=\dfrac{6}{5}\)
\(\dfrac{4}{5}\times\dfrac{7}{15}=\dfrac{4\times7}{5\times15}=\dfrac{28}{75}\)
Lời giải:
\(\frac{7}{2}+\frac{2}{25}=\frac{7\times 25+2\times 2}{2\times 25}=\frac{179}{50}\)
\(\frac{23}{5}-\frac{11}{3}=\frac{23\times 3-5\times 11}{5\times 3}=\frac{14}{15}\)
\(\frac{3}{7}-\frac{1}{14}=\frac{6}{14}-\frac{1}{14}=\frac{6-1}{14}=\frac{5}{14}\)
\(\frac{8}{5}: \frac{1}{3}=\frac{8}{5}\times 3=\frac{24}{5}\)
$2: \frac{5}{3}=\frac{2\times 3}{5}=\frac{6}{5}$
$\frac{4}{5}\times \frac{7}{15}=\frac{28}{75}$
`#qlv`
`(11)/(25) . (y + y5 - (23)/(55)) + 3/(14) . (56)/(25) = 1`
`=> (11)/(25) . (6y - (23)/(55)) + (12)/(25) = 1`
`=> (11)/(25) . (6y - (24)/(55)) = 1 - (12)/(25)`
`=> (11)/(25) (6y - (23)/(55)) = (13)/(25)`
`=> 6y - (23)/(55) = (13)/(25) : (11)/(25)`
`=> 6y - (23)/(55) = (13)/(11)`
`=> 6y = (13)/(11) + (23)/(55)`
`=> 6y = 8/5`
`=> y = 8/5 : 6`
`=> y = 8/5 . 1/6`
`=> y = 4/(15)`
Vậy `y = 4/(15)`
\(\dfrac{11}{25}\times\left(y+y\times5-\dfrac{23}{55}\right)+\dfrac{3}{14}\times\dfrac{56}{25}=1\)
\(\Rightarrow\dfrac{11}{25}\times\left(10\times y-\dfrac{23}{55}\right)+\dfrac{12}{25}-1=0\)
\(\Rightarrow\dfrac{22}{5}\times y-\dfrac{23}{125}-\dfrac{13}{25}=0\)
\(\Rightarrow\dfrac{22}{5}\times y=\dfrac{88}{125}\)
\(\Rightarrow y=\dfrac{88}{125}:\dfrac{22}{5}\)
\(\Rightarrow y=\dfrac{4}{25}\)