a, 8/35 : (-3 phần 9/20 )
giúp e vs e đang cần gấp
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\(2^{35}< 2^{36}=8^{12}\)
\(3^{24}=\left(3^2\right)^{12}=9^{12}\)
\(8^{12}< 9^{12}\)
=>\(2^{36}< 3^{24}\)
=>\(2^{35}< 3^{24}\)
g: \(=\dfrac{x^2+2x-x^2-4x-2x+4}{x\left(x-2\right)\left(x+2\right)}=\dfrac{-4x+4}{x\left(x-2\right)\left(x+2\right)}\)
h: \(=\dfrac{2x^2+1-x^2+1-x^2+x-1}{\left(x+1\right)\left(x^2-x+1\right)}\)
\(=\dfrac{x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{1}{x^2-x+1}\)
\(e,=\dfrac{1}{x-1}-\dfrac{2x}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{x^2-2x+1}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{\left(x-1\right)^2}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{x-1}{x^2+1}\\ f,=\dfrac{3x-1}{2\left(3x+1\right)}+\dfrac{3x+1}{2\left(3x-1\right)}-\dfrac{6x}{\left(3x-1\right)\left(3x+1\right)}\\ =\dfrac{9x^2-6x+1+9x^2+6x+1-12x}{2\left(3x-1\right)\left(3x+1\right)}=\dfrac{2\left(3x-1\right)^2}{2\left(3x-1\right)\left(3x+1\right)}=\dfrac{3x-1}{3x+1}\)
\(g,=\dfrac{x}{x\left(x-2\right)}-\dfrac{x^2+4x}{x\left(x-2\right)\left(x+2\right)}-\dfrac{2}{x\left(x+2\right)}\\ =\dfrac{x^2+2x-x^2-4x-2x+4}{x\left(x-2\right)\left(x+2\right)}=\dfrac{-4x+4}{x\left(x-2\right)\left(x+2\right)}\\ h,=\dfrac{2x^2+1-x^2+1-x^2+x-1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{1}{x^2-x+1}\)
`# \text {Kaizu DN}`
`a)`
`(3x + 6) + (7x - 14) = 0?`
\(\Rightarrow3x+6+7x-14=0\\ \Rightarrow\left(3x+7x\right)+\left(6-14\right)=0\\ \Rightarrow10x-8=0\\ \Rightarrow10x=8\Rightarrow x=\dfrac{8}{10}\\ \Rightarrow x=\dfrac{4}{5}\)
Vậy, \(x=\dfrac{4}{5}\)
`b)`
`17y + 35 + 4x + 17 = 42`
\(\Rightarrow\left(17y+17\right)+\left(35+4x\right)=42\\ \Rightarrow17\left(y+1\right)+\left(35+4x\right)=42\)
Bạn xem lại đề ;-;.
\(4\left(a^3+b^3\right)-6\left(a^2+b^2\right)\)
\(=4\left(a+b\right)^3-12ab\left(a+b\right)-6\left(a+b\right)^2+12ab\)
\(=4-6-12ab+12ab\)
=-2
1 I wish my students studied hard
2 I wish I could come to the party
3 I wish my grandparents didn't live too far from me
4 Nga wished she were in HN now
5 This room is cleaned everyday
\(\frac{8}{35}:\frac{-3}{\frac{9}{20}}=\frac{8}{35}:\frac{-20}{3}=\frac{8}{35}.\frac{3}{-20}=\frac{-6}{175}\)