Tìm x:
\(\dfrac{13}{12}\times x-\dfrac{5}{6}=\dfrac{4}{3}\)
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Những câu hỏi liên quan
C
13 tháng 2 2023
`5/9+4/9:x=1/3`
`=>4/9:x=1/3-5/9`
`=>4/9:x=3/9-5/9`
`=>4/9:x=-2/9`
`=>x=4/9:(-2/9)`
`=>x=4/9.(-9/2)`
`=>x=-4/2`
`=>x=-2`
VT
4 tháng 3 2023
\(\dfrac{-1}{4}< \dfrac{x}{24}< \dfrac{-1}{6}\\ \dfrac{-6}{24}< \dfrac{x}{24}< \dfrac{-4}{24}\\ \Rightarrow x=-5\)
10 tháng 2 2023
a: \(=\dfrac{-39+19+10}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)
b: \(=\dfrac{2^{30}\cdot3^{16}\cdot7-2^{34}\cdot3^{15}}{2^{28}\cdot3^{21}-2^{28}\cdot3^{17}}\)
\(=\dfrac{2^{30}\cdot3^{15}\left(3\cdot7-2^4\right)}{2^{28}\cdot3^{17}\left(3^4-1\right)}=\dfrac{2^2}{3^2}\cdot\dfrac{21-16}{80}=\dfrac{4}{9}\cdot\dfrac{5}{80}\)
\(=\dfrac{20}{720}=\dfrac{1}{36}\)
LN
Lưu Nguyễn Hà An
CTVHS
8 tháng 7 2023
chỉ cho biết mẫu số nên ta quy đồng mẫu số
4/7 < x/10 < 5/7 vậy
4/7 = 40/70
x/10 = x/70
5/7 = 50/70
vậy x là
41;42;43;44;45;46;47;48;49
ND
Nguyễn Đức Trí
VIP
8 tháng 7 2023
\(\dfrac{4}{7}< \dfrac{x}{10}< \dfrac{5}{7}\)
\(\Rightarrow\dfrac{4.10}{7.10}< \dfrac{7.x}{10.7}< \dfrac{5.10}{7.10}\)
\(\Rightarrow\dfrac{40}{70}< \dfrac{7.x}{70}< \dfrac{50}{70}\)
\(\Rightarrow7.x\in\left\{41;42;43;...49\right\}\)
\(\Rightarrow7.x\in\left\{42;49\right\}\) \(\left(x\in N\Rightarrow7.x⋮7\right)\)
\(7.x=42\Leftrightarrow x=6\)
\(7.x=49\Leftrightarrow x=7\)
2
7 tháng 2 2023
`6/7 . 8/13 +6/7 . 9/13+3/13 . 6/7`
`=6/7 . (8/13+9/13+3/13)`
`=6/7 . 20/13`
`=120/91`
VN
7 tháng 2 2023
\(\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{7}.\dfrac{9}{13}+\dfrac{3}{13}.\dfrac{6}{7}\)
\(=\dfrac{6}{7}.\left(\dfrac{8}{13}+\dfrac{9}{13}+\dfrac{3}{13}\right)\)
\(=\dfrac{6}{7}.\left(\dfrac{8+9+3}{13}\right)\)
\(=\dfrac{6}{7}.\dfrac{20}{13}\)
\(=\dfrac{6.20}{7.13}\)
\(=\dfrac{120}{91}\)
13 tháng 2 2023
\(-\dfrac{5}{7}\times\dfrac{2}{13}+\dfrac{-5}{7}\times\dfrac{3}{13}-\dfrac{5}{7}\times\dfrac{8}{13}\)
\(=-\dfrac{5}{7}\left(\dfrac{2}{13}+\dfrac{3}{13}+\dfrac{8}{13}\right)\)
\(=-\dfrac{5}{7}\times\dfrac{13}{13}\)
\(=-\dfrac{5}{7}\times1=-\dfrac{5}{7}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
10 tháng 7 2023
\(\dfrac{1}{3}-\dfrac{1}{12}-\dfrac{1}{20}-\dfrac{1}{30}-\dfrac{1}{42}-\dfrac{1}{56}-\dfrac{1}{72}-\dfrac{1}{90}-\dfrac{1}{110}=x-\dfrac{5}{13}\)
\(\dfrac{1}{3}\) - \(\dfrac{1}{3.4}\) - \(\dfrac{1}{4.5}\) - \(\dfrac{1}{5.6}\) - \(\dfrac{1}{6.7}\) - \(\dfrac{1}{7.8}\)- \(\dfrac{1}{8.9}\) - \(\dfrac{1}{9.10}\) - \(\dfrac{1}{10.11}\) = \(x\) - \(\dfrac{5}{13}\)
\(\dfrac{1}{3}\) - (\(\dfrac{1}{3.4}\) + \(\dfrac{1}{4.5}\) + \(\dfrac{1}{5.6}\) + \(\dfrac{1}{6.7}\)+ \(\dfrac{1}{7.8}\) + \(\dfrac{1}{8.9}\) + \(\dfrac{1}{9.10}\) + \(\dfrac{1}{10.11}\) =\(x\)-\(\dfrac{5}{13}\)
\(\dfrac{1}{3}\) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) +...+ \(\dfrac{1}{9}\) - \(\dfrac{1}{10}\) + \(\dfrac{1}{10}\) - \(\dfrac{1}{11}\)) = \(x\) - \(\dfrac{5}{13}\)
\(\dfrac{1}{3}\) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{11}\)) = \(x\) - \(\dfrac{5}{13}\)
\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{11}\) = \(x\) - \(\dfrac{5}{13}\)
\(x-\dfrac{5}{13}=\dfrac{1}{11}\)
\(x\) = \(\dfrac{1}{11}\) + \(\dfrac{5}{13}\)
\(x\) = \(\dfrac{68}{143}\)
Cách làm đây nhé bn
\(\dfrac{13}{12}\) x X - \(\dfrac{5}{6}\) = \(\dfrac{4}{3}\)
X - \(\dfrac{5}{6}\) = \(\dfrac{4}{3}\) : \(\dfrac{13}{12}\)
X - \(\dfrac{5}{6}\) = \(\dfrac{16}{13}\)
X = \(\dfrac{16}{13}\) + \(\dfrac{5}{6}\)
X = \(\dfrac{31}{78}\)