5 . 22 + ( x + 3 ) = 52
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a: \(\left|x\right|-\dfrac{38}{7}\left|x\right|-\dfrac{3}{4}=2\left|x\right|-\dfrac{8}{7}\)
\(\Leftrightarrow\left|x\right|\cdot\dfrac{-45}{7}=-\dfrac{8}{7}+\dfrac{3}{4}=\dfrac{-32+21}{28}=\dfrac{-11}{28}\)
=>|x|=11/180
=>x=11/180 hoặc x=-11/180
b: \(\Leftrightarrow x\cdot\dfrac{13}{4}-\dfrac{7}{6}x=\dfrac{5}{12}+\dfrac{5}{3}\)
=>25/12x=25/12
hay x=1
\(\dfrac{93}{17}:x+\left[\dfrac{-4}{17}\right]:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(=>\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}\)
\(=>\dfrac{89}{17}:x=\dfrac{-17}{286}\)
\(=>x=\dfrac{89}{17}:\dfrac{-17}{286}\)
\(=>x=\dfrac{-25454}{289}=-88\dfrac{22}{289}\)
a: \(61\cdot45+61\cdot23-68\cdot51\)
\(=61\left(45+23\right)-68\cdot51\)
\(=68\cdot61-68\cdot51\)
\(=68\left(61-51\right)=68\cdot10=680\)
b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)
\(=75-75+4\cdot8\)
\(=4\cdot8=32\)
c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)
\(=\dfrac{36}{20-30+4^2}\)
\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)
d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)
\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)
(93/17+-4/17) : x + 33/182=4/11
89/17 : x = 4/11 + 33/182
89/17 : x = Sia đề
\(\Rightarrow16-3x=504:72=7\\ \Rightarrow3x=16-7=9\Rightarrow x=3\\ \left(2^2\cdot x-5^2\right)\cdot3^8=3^9\\ \Rightarrow4x-25=3^9:3^8=3\\ \Rightarrow4x=28\Rightarrow x=7\)
Bài 2:
a. $=58(75+50-25)=58.100=5800$
b. $=27.8+4.9-5=216+36-5=247$
Bài 3:
a.
$(x-38):16=12$
$x-38=16\times 12=192$
$x=192+38 = 230$
b.
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
c.
$440+2(125-x)=546$
$2(125-x)=546-440=106$
$125-x=106:2=53$
$x=125-53=72$
d.
$(x-15):5+20=22$
$(x-15):5=22-20=2$
$x-15=2\times 5=10$
$x=10+15=25$
e.
$2x-138=2^3.3^2=8.9=72$
$2x=72+138 = 210$
$x=210:2=105$
a: \(ƯCLN=25\)
\(BCNN=5^2\cdot3\cdot7=525\)
b: \(ƯCLN=15\)
\(BCNN=3\cdot5\cdot11\cdot7\cdot2^2=9240\)
\(5\cdot2^2+\left(x+3\right)=5^2\)
\(5\cdot4+\left(x+3\right)=25\)
\(20+\left(x+3\right)=25\)
\(x+3=25-20\)
\(x+3=5\)
\(x=5-3\)
\(x=2\)
5.\(2^2\)+(x+3)=\(5^2\)
=>5.4+x+3=25
=>x=25-3-20
=>x=2