3/4 x 8/9 x 15/16 x ... x 120/121
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B=1x3/2x2x2x4/3x3x3x5/4x4x...x10x12/11x11
B=1x3x2x4x3x5x...x10x12/2x2x3x3x4x4x...x11x11
B=(1x2x3x...x10)x(2x3x5x...x12)/(2x3x4x...x11)x(2x3x4x...x11)
B=1x12/11x2
B=12/22
B=6/11
Vậy B = 6/11
Đặt \(A=\frac{1.2+2.4+3.6+4.8+5.10}{4+6.8+9.12+12.16+15.20}\)
\(\Rightarrow A=\frac{1.\left(1+2\right)+2.\left(1+2\right)+3.\left(1+2\right)+4.\left(1+2\right)+5.\left(1+2\right)}{4+2.\left(3+4\right)+3.\left(3+4\right)+4.\left(3+4\right)+5.\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+2+3+4+5\right).\left(1+2\right)}{4+\left(2+3+4+5\right).\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+5\right).5:2.\left(1+2\right)}{4+\left(2+5\right).4:2.\left(3+4\right)}\)
\(\Rightarrow A=\frac{6.5:2.3}{4+7.4:2.7}=\frac{45}{4+98}=\frac{45}{102}=\frac{15}{34}\)
Vậy \(A=\frac{15}{34}\)
Chúc bn học tốt
=2x2/1x3 x 3x3/2x4x4/3x5 x ... x 11x11/10x12
=2x2x3x3x4x4x...x11x11/1x3x2x4x3x5x...x10x12
= 2x3x4x...x11)x(2x3x4x...x11)/(1x2x3x4x...x11)/(1x2x3x...x10)x(2x3x4x...x11)
=11x2/1x12
=22/12
=11/6
4/3x9/8x16/15x...x121/120=\(\dfrac{2^2}{1\cdot3}\)x\(\dfrac{3^2}{2\cdot4}\)x\(\dfrac{4^2}{3\cdot5}\)x...x\(\dfrac{11^2}{10\cdot12}\)=\(\dfrac{2}{3}\)x\(\dfrac{11}{10}\)=\(\dfrac{11}{15}\)
\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.....\frac{120}{121}\)
\(=\frac{2.3.4......10}{2.3.4.....11}.\frac{3.4.5.....12}{2.3.4.....11}\)
\(=\frac{1}{11}.6=\frac{6}{11}\)
a: =11/4+5/4-9/8
=4-9/8=32/8-9/8=23/8
b: \(=\dfrac{6}{7}\cdot\dfrac{7}{4}+\dfrac{5}{3}=\dfrac{3}{2}+\dfrac{5}{3}=\dfrac{9+10}{6}=\dfrac{19}{6}\)
c: \(=\dfrac{13}{18}\cdot\dfrac{9}{5}-1=\dfrac{13}{10}-1=\dfrac{3}{10}\)
d: \(=3+\dfrac{9}{4}\cdot\dfrac{5}{3}=3+\dfrac{45}{12}=\dfrac{81}{12}=\dfrac{27}{4}\)
1+7=8, 7+8=15, 8+15= 23
Như vậy dãy số 1, 7, 8, 15, 23, đđược thành lập như sau: mỗi số trong dãy số bắt dầu từ số thứ ba là tổng của hai số đứng ngay trước nó. ( 0,5 điểm )
Dãy số được viết 1 + 7+ 8 + 15 + 23 + 38 + 61 + 99 + 160 = ( 1 điểm )
= 8 + 8 + 38 + 38 + 160 + 160 =
= 2 ( 8 + 38 + 160 ) =
= 412
1) 1 + 7 + 8 + 15 + 23 + 38 + 61 + 99 + 160
= 1 + (8 - 1) + (15 - 7) + (23 - 8) + (38 - 15) + (61 - 23) + (99 - 38) + (160 - 61) + (259 - 99) (gạch bỏ 8 với trừ 8 ; 1 với -1 ; .....; 99 với -99)
= -7 + 160 + 259 = 412.
x + (-405) , mà x = -121
suy ra x = (-121) + (-405)
x= -(121+405)
x= -526
vậy x = -526
Bài 2:
a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\)
= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))
= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)
= \(\dfrac{5}{23}\)
b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\) \(\times\) \(\dfrac{3}{9}\)
= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)
= \(\dfrac{14}{12}\)
= \(\dfrac{7}{6}\)
\(\dfrac{3}{4}\cdot\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot\cdot\cdot\dfrac{120}{121}\)
\(=\dfrac{1\cdot3}{2\cdot2}\cdot\dfrac{2\cdot4}{3\cdot3}\cdot\dfrac{3\cdot5}{4\cdot4}\cdot\cdot\cdot\dfrac{10\cdot12}{11\cdot11}\)
\(=\dfrac{1\cdot2\cdot3\cdot\cdot\cdot10\cdot3\cdot4\cdot5\cdot\cdot\cdot12}{2\cdot3\cdot4\cdot\cdot11\cdot2\cdot3\cdot4\cdot\cdot11}\)
\(=\dfrac{1\cdot12}{11\cdot2}\)
\(=\dfrac{12}{22}\)
\(=\dfrac{6}{11}\)