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16 tháng 8 2022

`40:8/9 = 40 xx 9/8 = 45`

`7/11 :28 = 7/11 xx 1/28 = 1/44`

13 tháng 7 2019

a) -1/4

b)10/11(-8/9+7/18)=10/11.(-1/2)=-5/11

c) 3/14.28-13/21.28+29/42.28-8=28(3/14-13/21+29/42)-8=28.2/7-8=8-8=0

11 tháng 2 2018

a,30-7-8+9-11

=(30-7-8-11)+9=4+9=13

b,40-2+(-40)-2+4

=(40-40)+(4-2-2)=0

c,15-2+(-7)-9+(-11)

=15-(2+7+9+11)=15-29=-14

d,28-1+35-36-27

=(28-27)(+(35-36)-1=1-1-1=-3

có j ko hiểu thì add fr mình nha :)))

29 tháng 7 2018

A)  7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11

=7/38.(9/11+4/11-2/11)

=7/38

B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20

=5/31.(21/25-7/10-9/20)

=5/31.(-31/100)

=-1/20

a: =9/11(7/4+5/4)=9/11x3=27/11

b: \(=\dfrac{28}{5}\cdot\dfrac{5}{8}\cdot\dfrac{5}{4}=\dfrac{28}{8}\cdot\dfrac{5}{4}=\dfrac{140}{32}=\dfrac{35}{8}\)

c: \(=\dfrac{2}{6}+\dfrac{4}{5}\cdot\dfrac{6}{5}-\dfrac{2}{5}=\dfrac{67}{75}\)

18 tháng 5 2022

a,=(7/4+5/4):11/9

=3:11/9

=27/11

b,=28/5.5/4.5/8

=7.5/8

=35/8

c,=1/3+24/25-2/5

=97/75-2/5

=67/75

a)\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)

=\(\dfrac{10}{11}.\dfrac{-8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)

=\(\dfrac{10}{11}(\dfrac{-8}{9}+\dfrac{7}{18})\)

=\(\dfrac{10}{11}.\dfrac{-1}{2}\)

=\(\dfrac{-5}{11}\)

7 tháng 8

b; 

B = \(\dfrac{3}{14}\) : \(\dfrac{1}{28}\) - \(\dfrac{13}{21}\)\(\dfrac{1}{28}\) + \(\dfrac{29}{42}\) : \(\dfrac{1}{28}\) - 8

B = (\(\dfrac{3}{14}\) - \(\dfrac{13}{21}\) + \(\dfrac{29}{42}\)) - 8

B = (\(\dfrac{9}{42}\) - \(\dfrac{26}{42}\) + \(\dfrac{29}{42}\)) - 8

B = (\(\dfrac{-17}{42}\) + \(\dfrac{29}{42}\)) - 8

B = \(\dfrac{2}{7}\) - 8

B = \(\dfrac{2}{7}-\dfrac{56}{7}\)

B = - \(\dfrac{54}{7}\)

13 tháng 7 2023

\(\dfrac{19}{28}+\dfrac{23}{47}-\dfrac{15}{8}+\dfrac{9}{28}+\dfrac{24}{47}\)

\(=\left(\dfrac{19}{28}+\dfrac{9}{28}\right)+\left(\dfrac{23}{47}+\dfrac{24}{47}\right)-\dfrac{15}{8}\)

\(=\dfrac{28}{28}+\dfrac{47}{47}-\dfrac{15}{8}\)

\(=1+1-\dfrac{15}{8}\)

\(=\dfrac{1}{8}\)

____________________

\(\dfrac{30}{11}+\dfrac{12}{35}-\dfrac{19}{11}-\dfrac{2}{35}-\dfrac{2}{7}\)

\(=\left(\dfrac{30}{11}-\dfrac{19}{11}\right)+\left(\dfrac{12}{35}-\dfrac{2}{35}\right)-\dfrac{2}{7}\)

\(=\dfrac{11}{11}+\dfrac{10}{35}-\dfrac{2}{7}\)

\(=1+\dfrac{2}{7}-\dfrac{2}{7}\)

\(=1\)